等待已运行进程的所有子进程完成C# [英] Wait for all child processes of a ran process to finish C#

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本文介绍了等待已运行进程的所有子进程完成C#的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在为游戏开发Launcher应用程序。就像XNA中的XBOX仪表板一样。我想在启动程序(游戏)退出时重新打开程序。使用一个简单的游戏,它可以正常工作:

I'm developing a Launcher application for games. Much like XBOX Dashboard in XNA. I want to open back my program when the process which it started(the game) exits. With a simple game this is working:

[DllImport("user32.dll")]
[return: MarshalAs(UnmanagedType.Bool)]
static extern bool SetForegroundWindow(IntPtr hWnd);

[DllImportAttribute("User32.DLL")]
private static extern bool ShowWindow(IntPtr hWnd, int nCmdShow);
private const int SW_SHOW = 5;
private const int SW_MINIMIZE = 6;
private const int SW_RESTORE = 9;

public void Run(file)
{
    ProcessStartInfo startInfo = new ProcessStartInfo(file);
    Environment.CurrentDirectory = Path.GetDirectoryName(file);
    startInfo.Verb = "runas";
    var process = Process.Start(startInfo);
    process.WaitForExit();
    ShowWindow(Game1.Handle, SW_RESTORE);
    SetForegroundWindow(Game1.Handle);
}

Game1.Handle来自:

The Game1.Handle is got from:

Handle = Window.Handle;

在Game1的加载内容方法中。

In the Game1's Load Content method.

我的问题是,在运行过程开始的所有子过程完成后,如何使窗口打开?

My question is how I can make the window open up after all the child process that the ran process has started is finished?

就像启动器启动游戏一样。

Like a launcher launches a game.

我想一些更高级的程序员可能会知道窍门。

I think some more advanced programmer may know the trick.

预先感谢!

推荐答案

您可以使用Process.Exited事件

You could use Process.Exited event

 int counter == 0;
     .....

     //start process, assume this code will be called several times
     counter++;
     var process = new Process ();
     process.StartInfo = new ProcessStartInfo(file);

     //Here are 2 lines that you need
     process.EnableRaisingEvents = true;
     //Just used LINQ for short, usually would use method as event handler
     process.Exited += (s, a) => 
    { 
      counter--;
      if (counter == 0)//All processed has exited
         {
         ShowWindow(Game1.Handle, SW_RESTORE);
        SetForegroundWindow(Game1.Handle);
         }
    }
    process.Start();

对游戏更合适的方法是使用名为信号灯,但我建议您从Exited事件开始,然后在了解其工作原理后,移至信号灯

More appropriate way for the game is to use named semaphore, but I would suggest you to start with Exited event, and then when you understand how it works, move to semaphore

这篇关于等待已运行进程的所有子进程完成C#的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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