如何轻松获得Scala案例类的名称？ [英] How can I easily get a Scala case class's name?

问题描述

给出：

case class FirstCC {
  def name: String = ... // something that will give "FirstCC"
}
case class SecondCC extends FirstCC
val one = FirstCC()
val two = SecondCC()

如何从 one.name FirstCC c $ c>和 SecondCC from two.name ？

How can I get "FirstCC" from one.name and "SecondCC" from two.name?

推荐答案

def name = this.getClass.getName

或者如果您只想要不带包装的名称：

Or if you want only the name without the package:

def name = this.getClass.getSimpleName

请参见 java.lang.Class 了解更多信息。

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