是否可以在不初始化类的情况下访问类属性？ [英] Is it possible to access class properties without initialising the class?

问题描述

我想访问将在调用构造函数时定义的类的所有属性，以便可以为该类实现某种接口。

I want to access all of the properties of a class that will be defined when the constructor is called, so that I can implement a sort of interface for the class.

说我有一个定义属性 hello 的类，我想访问它以检查它是否已实现并且分配给它的类型正确。问题是，由于所有非 static 类属性都绑定到一个实例，因此如果不实例化该类，我将无法获取它们，而这是无法做到的。

Say I had a class that defines the property hello, I would like to access it to check it has been implemented and the type assigned to it is correct. Problem is, since all non-static class properties are tied to an instance, I can't get at them without instantiating the class, which I can't do.

在这种情况下，可以访问 hello 吗？

In this situation, is it possible to access hello?

class MyClass {
    constructor () {
        this.hello = 'greetings';
    }
}

推荐答案

在这种情况下，是否可以访问你好？

并非不使用JavaScript解析器（就像IDE试图推断实例mbmers一样）。就像您说的那样，你好直到/除非创建了一个实例才作为属性存在。使用解析器，您可以（通常）确定属性名称是什么，也许有时是它们的初始值，但仅此而已。

Not without using a JavaScript parser (like IDEs do to try to infer instance mbmers). hello, as you say, doesn't exist as a property until/unless an instance is created. With a parser, you can (usually) determine what the property names will be, perhaps sometimes their initial values, but that's all.

这篇关于是否可以在不初始化类的情况下访问类属性？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！