通过命令行运行php脚本时如何加载Zend类 [英] How to load Zend classes when running php script by command lines

问题描述

我有一个需要Zend类的php脚本。它可以在浏览器中运行，但是在命令提示符下通过命令行运行脚本时会发生错误。

I have a php script needing Zend classes. It can be run in a browser, but errors occur when run the script by command lines in command prompt.

require_once 'Zend/Loader.php'; // It can work in a browser but failed by command lines

我也尝试过：

require_once 'C:\wamp\www\zf_project\library\Zend\Loader.php';

和

ini_set('include_path', 
ini_get('include_path') . 
PATH_SEPARATOR . 
dirname(__FILE__). DIRECTORY_SEPARATOR. 'library');

但是失败了。

然后我需要加载类：

Zend_Loader::loadClass('Zend_Rest_Client');

如何使用Zend类？

感谢您！

推荐答案

如果您要通过自动加载使用Zend类，而无需引导整个应用程序，需要在ZF1中进行操作（它似乎正在使用它）：

If all you want is to use Zend classes via autoloading—without bootstrapping your whole application—all you need to do in ZF1 (which it what you seem to be using):

<?php
// if ZF is not in your include path to begin with
set_include_path(implode(PATH_SEPARATOR, array('/path/to/zend/library', get_include_path())));
include 'Zend/Loader/Autoloader.php';
Zend_Loader_Autoloader::getInstance(); // registers autoloader

// now can access Zend classes without having to include
$client = new Zend_Http_Client(...);

另外请注意，您不需要调用 Zend_Loader :: loadClass 来加载类，当您在常规代码中使用类名时，自动加载器会自动完成此操作，例如，像我上面所做的那样，调用构造函数。

Also note, you don't need to call Zend_Loader::loadClass to load a class, this is done automatically by the autoloader when you use the class name in normal code, for example by calling the constructor as I've done above.

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