是否可以从PHP的闭包返回引用？ [英] Is it possible to return a reference from a closure in PHP?

问题描述

要从PHP函数中返回引用，必须执行以下操作：

In order to return a reference from a function in PHP one must:

...使用引用运算符&在
中，无论是函数声明还是将返回值分配给
a变量。

...use the reference operator & in both the function declaration and when assigning the returned value to a variable.

：

function &func() { return $ref; }
$reference = &func();

我正在尝试从闭包中返回引用。在一个简化的示例中，我要实现的是：

I am trying to return a reference from a closure. In in a simplified example, what I want to achieve is:

$data['something interesting'] = 'Old value';

$lookup_value = function($search_for) use (&$data) {
    return $data[$search_for];
}

$my_value = $lookup_value('something interesting');
$my_value = 'New Value';

assert($data['something interesting'] === 'New Value');

我似乎无法获得从函数工作返回引用的常规语法。

I cannot seem to get the regular syntax for returning references from functions working.

推荐答案

您的代码应如下所示：

$data['something interesting'] = 'Old value';

$lookup_value = function & ($search_for) use (&$data) {
    return $data[$search_for];
};

$my_value = &$lookup_value('something interesting');
$my_value = 'New Value';

assert($data['something interesting'] === 'New Value');

检查此退出：

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