使用闭包在python中模拟静态变量 [英] Simulate static variables in python with closures

问题描述

是否可以在python中编写一个函数，该函数接受参数a并输出h + a的结果，其中h是局部变量。然后它应该返回自身，并且h增加一个。

Is it possible to write a function in python, which takes an argument a and prints the result of h+a where h is a local variable. Then it should return itself, with h increased by one.

推荐答案

是的，您可以

def f(a):
    def inner(h, a):
        print h+a
        return lambda (x): inner(h+1, x)
    return inner(1, a)

示例

g = f(0) # +1
g = g(0) # +2
g = g(0) # +3

f(0) # +1
g(0) # +4
g(0) # +4

打印

1
2
3
1
4
4

QED

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