如何使用cmd中的默认应用程序打开文件？ [英] How to open file with default application in cmd?

问题描述

我正在尝试在用户创建文件后在默认编辑器中打开文件。到目前为止，我的脚本是：

I'm trying to open a file in it's default editor after the user has created the file. So far my script is:

@echo off
@echo --- Create A New File ---
@echo -
@echo Where should we put the new file?
set /p fileLocation=@ %UserProfile%\
@echo -
@echo What do you want to call your new file?
set /p fileName=@ 
@echo -
@echo Almost Done! What is the files extension?
set /p extension=@ .
@echo -
copy NUL "%UserProfile%\%fileLocation%\%fileName%.%extension%"

（忽略多余的回声和'@'只是为了好玩）

(ignore the extra echos and '@' those are just for fun)

点击文件后，命令：选择位置>选择文件名>选择文件扩展名。我几乎要完成我想要的，但是最后一件事。

After I click the file, it does the command: Choose Location > Choose File Name > Choose File extension. I'm almost done on what I want but theres one last thing. How can I get the file name that I created and then open in its default text-editor?

推荐答案

可以如何使用创建的文件名？ c $ c>开始以使用关联的应用程序打开文件。

You can use start to open the file with the associated application.

资源：

• 使用Windows命令行（不使用JDIC）在默认应用程序中打开文件

• Open a File in the Default Application using the Windows Command Line (without JDIC)

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