从文本文件读取变量 [英] Read a variable from a text file

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本文介绍了从文本文件读取变量的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试创建一个密码提示,该提示将用户输入与文本文件中的信息进行比较(密码保存在.txt文件中)。

I'm trying to create a password prompt which compares the user input to information in a text file (the password is saved in the .txt file).

我已经尝试使用通过命令提示符和此网站提供给我的信息,但是我无法使其正常工作,可能是因为我没有足够的经验,因为我不太熟悉高级批处理编码。

I've tried to work with information provided to me through the command prompt and and this website but I just can't get it to work, probably because i don't have sufficient experience as I'm rather new to advanced batch coding.

到目前为止,这是我想出的,文本文件的名称为Q47.txt,其中只有 hello一词,直到我可以使其工作:

This is what I've come up with so far, the name of the text file is Q47.txt and in it is just the word "hello" until I can get this to work:

@echo off  
:a  
cls  
SetLocal EnableDelayedExpansion  
set content=  
for /F "delims=" %%i in (Q47.txt) do set content=!content! %%i  
echo %content%  
EndLocal  

echo Enter password to continue:  
set /p "VAR=>"  
    if "%VAR%" == "%content%" (  
    goto begin  
    )  
echo Incorrect, please try again.  
pause >nul  
goto a      


:begin  
cls  
echo Welcome  
pause >nul      

请您告诉我我哪里出问题了。

Please can you tell me where I've gone wrong.

我还想知道如何消除变量前的空格。

I'd also like to know how to eliminate the space before the variable.

推荐答案

您可以尝试以下操作:

@ECHO OFF &SETLOCAL
:a  
set "content="  
for /F "tokens=*" %%i in (Q47.txt) do set "content=%%i" 
echo "%content%"  

echo Enter password to continue:  
set /p "VAR=>"  
if "%VAR%" == "%content%" goto begin  
echo Incorrect, please try again.  
pause >nul  
goto a      

:begin  
cls  
echo Welcome  
pause >nul      

这篇关于从文本文件读取变量的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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