NSTableView内NSTextFieldCell中的可点击网址链接？ [英] Clickable url link in NSTextFieldCell inside NSTableView?

问题描述

我在NSTextFieldCell中有一个NSAttributedString。它创建了几个可单击的URL链接，并在NSTextFieldCell中放入了一个大的NSAttributedString。每当我正常查看NSTextFieldCell并将其突出显示时，我都无法单击链接。

如果设置了TableView，以便单击时可以编辑每一列或每一行两次，进入编辑模式并查看NSTextFieldCell的内容，我的链接显示出来并且可以单击。当我单击该行之外的内容时，将不再看到可单击的链接。

我必须处于编辑模式才能查看链接或单击它们。 / p>

我觉得我缺少某些设置。

解决方案

我认为技术说明无法回答问题，即如何在NSTableView单元格中放置链接。我发现最好的方法是为表格单元格使用一个按钮单元格。假定只有链接将在表的特定列中。

在Interface Builder中，将NSButton单元格拖到想要链接的表列中。

p>

在您的表视图委托中，实现tableView：dataCellForTableColumn：row：如下：

 -（NSCell *）tableView：（NSTableView *）tableView 
 dataCellForTableColumn：（NSTableColumn *）列
行：（NSInteger）行
 {
 NSButtonCell * buttonCell = nil ; 
 NSAttributedString * title =无; 
 NSString * link = nil; 
 NSDictionary *属性=无； 
 
 //整行的单元格-如果（column == nil）
 return（nil）;我们不做标题
； 
 
 //除了link以外的其他列都可以正常执行
 if（！[self isLinkColumn：column]）//根据您的表实现此功能
 return（[column dataCellForRow ：行]）; 
 
 //如果没有链接，没有按钮，则只是一个空白文本字段
 if（（link = [self linkForRow：row]）！= nil）//根据您的需要实施此操作表
 return（[[[[NSTextFieldCell alloc] initTextCell：@] autorelease]）; 
 
 //这是一个链接。创建标题
属性= [[NSDictionary分配] initWithObjectsAndKeys：
 [NSFont systemFontOfSize：[NSFont systemFontSize]]，NSFontAttributeName，
 [NSNumber numberWithInt：NSUnderlineStyleSingle]，NSUnderlineStyleAttributeName，
 NSColor blueColor]，NSForegroundColorAttributeName，
 [NSURL URLWithString：link]，NSLinkAttributeName，nil]; 
 title = [[NSAttributedString alloc] initWithString：link properties：attributes]; 
 [属性发布]； 
 
 //创建一个按钮单元
 buttonCell = [[[NSButtonCell alloc] init] autorelease]; 
 [buttonCell setBezelStyle：NSRoundedBezelStyle]; 
 [buttonCell setButtonType：NSMomentaryPushInButton]; 
 [buttonCell setBordered：NO]; //不需要带边框的按钮
 [buttonCell setAttributedTitle：title]; 
 [标题发布]； 
 return（buttonCell）; 
} 
  

将表的目标/操作设置为委托人并检查是否单击链接列：

 -（void）clickTable：（NSTableView *）发送者
 {
 NSTableColumn * column = [[sender tableColumns] objectAtIndex：[sender clickedColumn]]; 
 NSInteger row = [发送者clickedRow]; 
 NSString * link = nil; 
 
 if（[self isLinkColumn：column]&&（link = [self linkForRow：row]）！= nil）
 [[NSWorkspace sharedWorkspace] openURL：[NSURL URLWithString：link ]]; 
} 
  

现在，链接看起来像，但单击它实际上是按下按钮，您可以在操作方法中进行检测并使用NSWorkspace进行调度。

I have a NSAttributedString that I'm using in a NSTextFieldCell. It makes several clickable url links and puts a big NSAttributedString inside the NSTextFieldCell. Whenever I am viewing the NSTextFieldCell normally and it's highlighted, I cannot click on the links.

If I set the TableView so I can edit each column or row, when I click twice, go into Edit mode and view the NSTextFieldCell contents, my links show up and are clickable. When I click away from the row, I can no longer see clickable links.

I have to be in "edit" mode to see the links or click on them.

I feel like there's some setting I'm just missing.

解决方案

I don't think the tech note answers the question, which was how to put a link in an NSTableView cell. The best way I've found to do this is to use a button cell for the table cell. This assumes that only links will be in a particular column of the table.

In Interface Builder, drag an NSButton cell onto the table column where you want the links.

In your table view delegate, implement tableView:dataCellForTableColumn:row: as follows:

- (NSCell *) tableView: (NSTableView *) tableView
    dataCellForTableColumn: (NSTableColumn *) column
    row: (NSInteger) row
{
    NSButtonCell *buttonCell = nil;
    NSAttributedString *title = nil;
    NSString *link = nil;
    NSDictionary *attributes = nil;

// Cell for entire row -- we don't do headers
    if (column == nil)
        return(nil);

// Columns other than link do the normal thing
    if (![self isLinkColumn:column]) // Implement this as appropriate for your table
        return([column dataCellForRow:row]);

// If no link, no button, just a blank text field
    if ((link = [self linkForRow:row]) != nil) // Implement this as appropriate for your table
        return([[[NSTextFieldCell alloc] initTextCell:@""] autorelease]);

// It's a link. Create the title
    attributes = [[NSDictionary alloc] initWithObjectsAndKeys:
        [NSFont systemFontOfSize:[NSFont systemFontSize]], NSFontAttributeName,
        [NSNumber numberWithInt:NSUnderlineStyleSingle], NSUnderlineStyleAttributeName,
        [NSColor blueColor], NSForegroundColorAttributeName,
        [NSURL URLWithString:link], NSLinkAttributeName, nil];
    title = [[NSAttributedString alloc] initWithString:link attributes:attributes];
    [attributes release];

// Create a button cell
    buttonCell = [[[NSButtonCell alloc] init] autorelease];
    [buttonCell setBezelStyle:NSRoundedBezelStyle];
    [buttonCell setButtonType:NSMomentaryPushInButton];
    [buttonCell setBordered:NO]; // Don't want a bordered button
    [buttonCell setAttributedTitle:title];
    [title release];
    return(buttonCell);
}

Set the target/action for the table to your delegate and check for clicks on the link column:

- (void) clickTable: (NSTableView *) sender
{
    NSTableColumn *column = [[sender tableColumns] objectAtIndex:[sender clickedColumn]];
    NSInteger row = [sender clickedRow];
    NSString *link = nil;

    if ([self isLinkColumn:column] && (link = [self linkForRow:row]) != nil)
        [[NSWorkspace sharedWorkspace] openURL:[NSURL URLWithString:link]];
}

Now the link looks like a link, but a click on it is actually a button press, which you detect in the action method and dispatch using NSWorkspace.

这篇关于NSTableView内NSTextFieldCell中的可点击网址链接？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！