如何获得子视图在UITableViewCell中相对于整个窗口的位置？ [英] How do I get the position of subview in my UITableViewCell with respect to the whole window?

问题描述

我知道 convertRect：toRect 是这里的关键，但是我不确定如何调用它。我有一个单元格的子视图，我想要它在应用程序整个窗口中的位置。

I know convertRect:toRect is the key here, but I'm not sure how to call it. I have a subview of my cell, and I want its position in the app's entire window.

在目标操作方法中点击此按钮（子视图）时，我需要知道这一点。我想，我想在单元格上调用 convertRect：toRect 函数，以获得正确的坐标，但是在这种方法中，我没有引用单元格本身。

I need to know this when I tap on this button (the subview) in its target action method. I need to call the convertRect:toRect function on the cell, I figure, in order to get the right coordinates, but in this method I have no reference to the cell itself.

我是否爬上了超级视图层次结构？这似乎很糟糕，因为我不太确定会得到什么，因为它已嵌入单元格的contentView中，而Apple确实使用其私人子视图和其他功能进行了古怪的操作。

Do I climb the superview hierarchy? That seems gross, as I'm not totally sure what I would get, as it's embedded in the contentView of the cell, and Apple does wacky stuff with their private subviews and whatnot.

代码：

@IBAction buttonPressed(sender: UIButton) {
    // This button got the callback that it was pressed. It's in a cell. I need to convert its rect to that of the window here. I need the coordinate system it's calculated from (the cell) which I'm not sure of how to easily do in a target action callback.
}

推荐答案

实际上非常简单：

CGRect windowRect = [someSubview convertRect:someSubview.bounds toView:nil];

假设您有一个按钮处理程序：

Assuming you have a button handler:

- (void)someButtonHandler:(id)sender {
    UIButton *button = sender;

    // do your stuff

    CGRect windowRect = [button convertRect:button.bounds toView:nil];
}

当然，如果将方法设置为：

Of course it's even easier if your method is setup as:

- (void)someButtonHandler:(UIButton *)button {
}

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