Swift:如何解码来自api的结果,该结果是以字符串或数组字符串的形式返回的? [英] Swift: How to decode result from api which is being returned as a string or as a string of array?
问题描述
我正在使用NSUrlConnection和Apple的Codable库。
I am using NSUrlConnection and Codable library of Apple.
我正在使用Web API为应用程序注册新用户。 API返回状态和消息(在json中,我映射到模型)。
I am using a web API to signup new users for my application. The API returns a status and a message (in json which i map to a model).
这是我的模型类:
Struct SignUpResult {
let message: String
let status: String
}
Struct SignUpParams {
let name: String
let email: String
let mobile_no: String
let password: String
}
如果用户正确输入了所有参数,则消息将以字符串形式返回。像这样:
If the user gave all the parameters correctly then the message is returned as a string. Like this:
{
"status": "OK",
"message": "User signup successfully"
}
另一方面,如果用户输入的参数不正确,则该消息以数组形式返回。像这样:
On the other hand, if the user entered the parameters incorrectly then the message is returned as an array. Like this:
{
"status": "INVALID_PARAMS",
"message": [
"The name may only contain letters."
]
}
如果参数不正确,则会出现错误
If the parameters are incorrect then i get the error
"expected to decode a string but found an array instead".
这是我收到以下错误的代码:
This is the code i get the error on:
let result = JSONDecoder().decode(SignUpResult.self, from: data)
我该怎么办?
推荐答案
我的建议是解码状态
作为枚举
,并有条件地将消息
解码为 String
或 [String]
。 消息
被声明为数组。
My suggestion is to decode status
as enum
and conditionally decode message
as String
or [String]
. messages
is declared as array.
enum SignUpStatus : String, Decodable {
case success = "OK", failure = "INVALID_PARAMS"
}
struct SignUpResult : Decodable {
let messages : [String]
let status: SignUpStatus
private enum CodingKeys : String, CodingKey { case status, message }
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
status = try container.decode(SignUpStatus.self, forKey: .status)
switch status {
case .success: messages = [try container.decode(String.self, forKey: .message)]
case .failure: messages = try container.decode([String].self, forKey: .message)
}
}
}
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