根据覆盖率报告删除未使用的JavaScript代码 [英] Remove unused javascript code based on coverage report

问题描述

有一个很大的javascript库（〜40 000行代码），一个应用程序使用的库代码不到 50％。

There is a big javascript library (~ 40 000 lines of code) and an application which uses less than 50% of the library's code.

有一个利用库中所有必需功能并可以生成覆盖率报告的测试。

There is a test which utilizes all the needed functionality from the library and can produce coverage report.

如何以编程方式删除依赖于该测试的所有未使用的代码行？

How to remove programmatically every unused line of code relying on the test?

注意：覆盖率报告包含已执行行的索引，但不正确：忽略右括号，使用方法名的行

Note: coverage report contains indices of lines which were executed but it is not accurate: closing braces are ignored, lines with method names are marked as executed even if the method body was not etc.

推荐答案

您可以尝试使用：

npm install -g fixmyjs
fixmyjs <filename or folder>

这是 fixmyjs项目

这是一个很棒的清理工具，它似乎与某些版本的ecmascript不兼容

it is a great tool for cleanup, it appears to lack compatibility with some versions of ecmascript

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