使用相同的输入在codeigniter中上传多个图像 [英] uploading multiple image in codeigniter using same input
问题描述
视图
<form action="" method="POST" enctype="multipart/form-data">
<input type="file" name="userfile[]" size="40" multiple/>
<input type="submit" name="submit" value="Upload">
</form>
控制器
public function image()
{
$data['error'] = '';
$this->load->model('StackM');
if(isset($_POST['submit']))
{
$data['update_pass_error_msg'] = $this->StackM->add_multiple_image();
}
$this->load->view('stack_view');
}
Model
public function add_multiple_image(){
if((!empty($_FILES['f2']['name'])))
{
$config['upload_path'] = 'uploads/';
$config['allowed_types'] = 'gif|jpg|png|jpeg';
$files = $_FILES;
if ($files['f2']['name'][0] == '' )
{
# code...
return "Select a file to upload";
}
else
{
$mum_files = count($files['f2']);
for($i=0; $i<$mum_files; $i++)
{
if ( isset($files['f2']['name'][$i]) )
{
$config['file_name'] = time().'-'.$files['f2']['name'][$i];
$this->load->library('upload', $config);
$_FILES['f2']['name']= $files['f2']['name']["$i"];
$_FILES['f2']['type']= $files['f2']['type']["$i"];
$_FILES['f2']['tmp_name']= $files['f2']['tmp_name']["$i"];
$_FILES['f2']['error']= $files['f2']['error']["$i"];
$_FILES['f2']['size']= $files['f2']['size']["$i"];
$filename = rand().'-'.$_FILES['f2']['name'];
if (!empty($this->upload->do_upload('f2')))
{
$dataInfo[] = $this->upload->data();
$all_imgs = '';
if ( count($dataInfo) > 0) {
# code...
foreach ($dataInfo as $info) {
# code...
$all_imgs .= $info['file_name'];
$all_imgs .= ',';
}
}
}
}
}
}
}
else{
$all_imgs = "";
}
}
}
else{
$all_imgs = $this->session->userdata('image');
}
$this->db->insert('table_name', $all_imgs);
我在这段代码中面临的问题是想想如果我要添加7张图像，但是它正在显示数据库中只有5张图像，它占用的图像不超过5张，我还想在编辑表单时知道是否不想更改图像，那么它应该保持相同的图像，因此我将旧图像存储在会话中并检查是否存在为空，则只有会话变量。
但是在我的代码中，如果我不上传新图像，则如果我保留旧图像，那么它将保存空白
The problem I am facing in this code is Think suppose if I am adding 7 images, but it's showing only 5 images in database it's not taking more then five and also I want to know while editing the form if I don't want to change the image then it should remain same image so i have stored the old image in session and checking if it is empty then only it should session variable . But In my code if I will not upload new one If I keep old image as then it will save blank
推荐答案
为避免偏移量错误，在for循环内，您需要检查是否设置了数组索引：
这里有一个演示代码，可以在CodeIgniter中上载多个文件：
To avoid the offset error, inside of for loop you need to check if that array index is set or not: Here I have a demo code to upload multiple files in CodeIgniter:
views / stack_view.php
views/stack_view.php
<?php if ($this->session->flashdata('status')) { ?>
<h5><?=$this->session->flashdata('status')?>: <?=$this->session->flashdata('message')?></h5>
<?php } ?>
<?=form_open_multipart('stack', array('id' => 'my_id'))?>
<input type="file" name="userfile[]" size="40" multiple/>
<input type="submit" name="submit" value="Upload">
<?=form_close()?>
controllers / Stack.php
controllers/Stack.php
<?php
defined('BASEPATH') OR exit('No direct script access allowed');
class Stack extends CI_Controller {
public function __construct()
{
parent::__construct();
$this->load->library('session');
$this->load->helper(array('form', 'url'));
}
public function index()
{
if ($this->input->post('submit')) {
$config['upload_path'] = './uploads/';
$config['allowed_types'] = 'gif|jpg|png|jpeg';
$files = $_FILES;
if ($files['userfile']['name'][0] == '' ) {
# code...
$this->session->set_flashdata('status', 'error');
$this->session->set_flashdata('message', "Select a file to upload");
}
else
{
$mum_files = count($files['userfile']);
$dataInfo = array();
for($i=0; $i<$mum_files; $i++)
{
if ( isset($files['userfile']['name'][$i]) ) {
$config['file_name'] = time().'-'.$files['userfile']['name'][$i];
$this->load->library('upload', $config);
$_FILES['userfile']['name']= $files['userfile']['name']["$i"];
$_FILES['userfile']['type']= $files['userfile']['type']["$i"];
$_FILES['userfile']['tmp_name']= $files['userfile']['tmp_name']["$i"];
$_FILES['userfile']['error']= $files['userfile']['error']["$i"];
$_FILES['userfile']['size']= $files['userfile']['size']["$i"];
$filename = rand().'-'.$_FILES['userfile']['name'];
if ( ! $this->upload->do_upload('userfile'))
{
$error_message = $this->upload->display_errors();
$this->session->set_flashdata('status', 'error');
$this->session->set_flashdata('message', "$error_message");
}
else
{
//$data = array('upload_data' => $this->upload->data());
$this->session->set_flashdata('status', 'success');
$this->session->set_flashdata('message', "Files upload is success");
}
$dataInfo[] = $this->upload->data(); //all the info about the uploaded files are stored in this array
}
}
//here you can insert all the info about uploaded file into database using $dataInfo
$all_imgs = '';
if ( count($dataInfo) > 0) {
# code...
foreach ($dataInfo as $info) {
# code...
$all_imgs .= $info['file_name'];
$all_imgs .= ',';
}
}
$insert_data = array(
'your_column_name' => rtrim($all_imgs,",")
);
$this->db->insert('your_table_name', $insert_data);
}
}
$this->load->view('stack_view');
}
}
尝试此脚本，希望您将从中获得一些帮助。
Try this script and I hope you will get some help from this.
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