简单的Codeigniter表单验证 [英] Simple Codeigniter form validation

问题描述

我的登录表单有这样的问题

I am having some problem in my login form like this

我想在每个字段旁边显示一个单独的错误

I want to display an individually error beside of each field

这是控制器

function index()
{      
        $this->form_validation->set_rules('username','Username','trim|required|exact_length[4]|xss_clean');
        $this->form_validation->set_rules('password','Password','trim|required|min_length[4]|max_length[40]|xss_clean|callback_login');
        $this->form_validation->set_rules('jabatan','Jabatan','trim|required|xss_clean');

        if($this->form_validation->run() == false)
        {
            $this->load->view('login');
        }
        else
        {
            $this->load->view('welcome_message');
        }

}

function login()
{
    $username = $this->input->post('username');
    $password = $this->input->post('password');
    $jabatan = $this->input->post('jabatan');

    $value = $this->m_login->login($username,$password,$jabatan);

    if($value)
    {
        return true;
    }
    else
    {
        $this->form_validation->set_message('login', 'password salah');
        //delete redirect() and showing blank white screen
        return false;

    }

我做了 <？ PHP的回声form_error（）; ？> 每个字段旁边

<?php echo form_open('c_login/login'); ?>
            <table>
                <tr>
                    <td>Username</td>
                    <td><?php $inusername=array('name' => 'username', 'class' => 'GUI'); echo form_input($inusername); ?></td>
                    <td class="error"><?php echo form_error('username'); ?></td>
                </tr>

                <tr>
                    <td>Password</td>
                    <td><?php $inpassword=array('name' => 'password', 'class' => 'GUI', 'type' =>'password'); echo form_input($inpassword); ?></td>
                    <td class="error"><?php echo form_error('password'); echo $this->session->flashdata('login'); ?></td>
                </tr>

                <tr>
                    <td>Jabatan</td>
                    <td><?php $injabatan=array('keuangan' => 'keuangan', 'admin' => 'admin', 'hd' => 'head divisi', 'direktur' => 'direktur'); echo form_dropdown('jabatan',$injabatan,'keuangan','class = "gui"'); ?></td>
                    <td class="error"><?php echo form_error('jabatan'); ?></td>
                </tr>

                 <tr>
                    <td></td>
                    <td><?php $insubmit=array('name' =>'login','class' =>'button','value' => 'Login'); echo form_submit($insubmit); echo nbs(); $inreset=array('name' =>'reset','class' =>'button','value' => 'Hapus'); echo form_reset($inreset); ?></td>
                    <td class="error"><?php echo form_error(); ?></td>
                </tr>
            </table>
            <?php echo form_close(); ?>

form_error（）函数的作用是当我单击使用用户名和密码 echo 执行任何操作c>字段留空吗？

How come the form_error() function is not echoing anything when I click login with the username and password field left blank?

推荐答案

您知道验证中的问题，您正在检查类索引方法中的验证，而不是您的类和表单的登录方法已对ci_login / login方法采取了措施，如果登录失败，它将进行重定向，并且其清除表单验证也会验证您在登录方法上的字段，并将所有错误消息放入会话和显示中，脚本的某些更改已在此链接上查看代码已修改

you know problem in your validation you're checking validation in index method of your class not in login method of your class and in your form you have given action to ci_login/login method which is redirecting if login is failed and its clearing form validation validate your fields on login method also and put all error message in session and display, i have made some changes in script have look here on this link Code modified

为此更改，您必须使用url帮助器

for this changes you have to use url helper

function index()
{
    $this->form_validation->set_rules('username','Username','trim|required|exact_length[4]|xss_clean');
    $this->form_validation->set_rules('password','Password','trim|required|min_length[4]|max_length[40]|xss_clean|callback_login');
    $this->form_validation->set_rules('jabatan','Jabatan','trim|required|xss_clean');

    if($this->form_validation->run() == false)
    {
        $this->load->view('login');
    }
    else
    {
        //to check if the validation run correctly
        //$this->load->view('welcome_message');

        $username = $this->input->post('username');
        $password = $this->input->post('password');
        $jabatan = $this->input->post('jabatan');

        $value = $this->m_login->login($username,$password,$jabatan);

        if($value)
        {
            redirect('welcome_message');
            //return true;
        }
        else
        {
            $this->form_validation->set_message('login', 'password salah');
            redirect('c_login',$login); //i want to pass $login into login form, then print
            return false;               //them as a form_error

        }
    }

}


<?php echo form_open(uri_string()); ?>
<table>
    <tr>
        <td>Username</td>
        <td><?php $inusername=array('name' => 'username', 'class' => 'GUI'); echo form_input($inusername); ?></td>
        <td class="error"><?php echo form_error('username'); ?></td>
    </tr>

    <tr>
        <td>Password</td>
        <td><?php $inpassword=array('name' => 'password', 'class' => 'GUI', 'type' =>'password'); echo form_input($inpassword); ?></td>
        <td class="error"><?php echo form_error('password'); echo $this->session->flashdata('login'); ?></td>
    </tr>

    <tr>
        <td>Jabatan</td>
        <td><?php $injabatan=array('keuangan' => 'keuangan', 'admin' => 'admin', 'hd' => 'head divisi', 'direktur' => 'direktur'); echo form_dropdown('jabatan',$injabatan,'keuangan','class = "gui"'); ?></td>
        <td class="error"><?php echo form_error('jabatan'); ?></td>
    </tr>

     <tr>
        <td></td>
        <td><?php $insubmit=array('name' =>'login','class' =>'button','value' => 'Login'); echo form_submit($insubmit); echo nbs(); $inreset=array('name' =>'reset','class' =>'button','value' => 'Hapus'); echo form_reset($inreset); ?></td>
        <td class="error"><?php echo form_error(); ?></td>
    </tr>
</table>
<?php echo form_close(); ?>

这篇关于简单的Codeigniter表单验证的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！