PHP:从数组获取数据 [英] PHP: Get data from array
问题描述
我在控制器上有以下查询:
I have this query on my controller:
$this->db->select('t1.act_id, t2.login, t1.cust_name, t1.act_type, t1.act_detail, t1.date_added, t1.date_modified, t1.act_notes, '
. 't3.category, t1.total_time, sum(t1.total_time) as total')
->from('activity as t1')
->join('user as t2', 't1.user_id = t2.user_id', 'LEFT')
->join('customer as t3', 't1.cust_name = t3.cust_name', 'LEFT')
->where('t2.login', $user)
->where('MONTH(t1.date_added)', $month)
->order_by('t1.date_added', "desc");
$query = $this->db->get();
$result = $query->result_array();
$data = array('title' =>'Sales Report'." - ".$user,
'user' => $result);
$this->load->view('admin/report/vw_report_excel', $data);
我要发布此SUM值
总和(t1.total_time)总计
sum(t1.total_time) as total
但我不断收到错误消息,说获取非对象的属性
but I kept getting error, saying that "Trying to get property of non-object"
这是我在视图中调用它的方式(vw_report_excel):
here's how I called it on my view (vw_report_excel):
<?php echo ($user->total); ?>
如何正确调用或声明它?
问候
how is the correct way to call or declare it? Regards
这是我的观点,我希望将SUM从表/循环中排除。
here's my view, I want my SUM exclude from the table/loop.
<?php $i=1; foreach($user as $xuser) { ?>
<tr>
<td><?php echo $xuser['act_id']; ?></td>
<td><?php echo $xuser['login']; ?></td>
<td><?php echo $xuser['cust_name']; ?></td>
<td><?php echo $xuser['act_type']; ?></td>
<td><?php echo $xuser['act_detail']; ?></td>
<td><?php echo $xuser['date_added']; ?></td>
<td><?php echo $xuser['date_modified']; ?></td>
<td><?php echo $xuser['act_notes']; ?></td>
<td><?php echo $xuser['category']; ?></td>
<td><?php echo $xuser['total_time']; ?></td>
</tr>
<?php $i++; } ?>
<td><?php echo count($user); ?></td>
<td><?php echo ($user->total); ?></td>
推荐答案
result_array()
result_array()
此方法以纯数组或空$返回查询结果没有结果的b $ b数组。通常,您将在
foreach循环中使用它,如下所示:
This method returns the query result as a pure array, or an empty array when no result is produced. Typically you’ll use this in a foreach loop, like this:
因此请使用 foreach ()
foreach($user as $usr){
echo $usr['total'];
}
或使用:- <?php echo $ user [0] ['total']; ?>
(基于您对问题的代码修改)
Or use:-<?php echo $user[0]['total']; ?>
(Based on your code modification in your question)
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