回显用户信息在Codeigniter中不起作用 [英] echoing user information not working in Codeigniter

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本文介绍了回显用户信息在Codeigniter中不起作用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

大家好,我正在codeigniter框架上开发应用程序,我正在尝试回显特定用户的用户信息,但实际上并不能正常工作。名称未回显。

Hello guys I'm making application on the codeigniter framework and I'm trying to echo user info of a specific user but its not really working. The name is not being echoed. Also all the emails of the users in my database are being echoed.

(指向正确的tuser配置文件的链接虽然有效,但是链接的名称无效。
这是我的视图文件:

( The link to the right tuser profile works though but the name of the link doesn't. Its a blank link. This is my view file:

 foreach($userdetail_list as $row): ?>
<tr>
    <td>
        <a href="<?php echo base_url() . 'User/userdetails/'.$row['user_id']?>">
          <?php echo $row['voornaam']; ?>
        </a>
    </td>
    <td>
        <?php echo $row['email'];?>
    </td>
</tr>
<?php endforeach;  ?>

我的模型文件:

function getdata($user_id){
  $this->db->select("*"); 
  $this->db->from('users');
  $this->db->where('user_id', $user_id);
  $query = $this->db->get();
  return $query->result();
 }

    public function getUserInfo($user_id) {
        $arrReturn = array();
        $this->db->select('*');
        $this->db->from('users');
        $this->db->where('user_id', $user_id);
        $query = $this->db->get();
        $result = $query->result_array();
        if (!empty($result)) {
            $arrReturn = $result[0];
        }
        return $arrReturn;
    }

我的控制器文件:

public function userdetails($user_id)
 {
  //load the User_model
  $this->load->model('User_model');

  //call function getdata in de Product_model
  $data['userdetail_list'] = $this->User_model->getdata($user_id);

  $data['user'] = $this->User_model->getUserInfo($user_id);

  //laad view
  $data['main_content'] = 'profiel_user';
  $data['main_content'] = 'details';
  $this->load->view('profiel_user',$data);
 }

所以基本上在视图文件上,我只希望1个电子邮件被回显为1使用user_id而不是所有用户电子邮件的特定用户,我也想在视图页面上看到未回显的名称及其空白链接。名称= voornaam

So basically on the view file, I only want 1 email being echoed of 1 specific user with using the user_id and not all the user emails, also I want to see the name on the view page which is not being echoed and its a blank link. name = voornaam

推荐答案

尝试这样

模型函数

// Gets a list of multiple users.
function getdata(){
    $query = $this->db->get('users');
    return $query->result_array();
}

// Gets the users information 
public function getUserInfo($user_id) {
    $this->db->where('user_id', $user_id);
    $query = $this->db->get('users');
    return $query->row_array();
}

控制多个用户

public function userdetails($user_id) {

    $this->load->model('user_model');

    $data['userdetail_list'] = $this->user_model->getdata();

    $this->load->view('profiel_user', $data);

}

查看多个用户列表

<?php foreach($userdetail_list as $row){ ?>
    <tr>
        <td>
            <a href="<?php echo base_url('user/userdetails/'.$row['user_id']);?>">
              <?php echo $row['voornaam']; ?>
            </a>
        </td>
        <td>
            <?php echo $row['email'];?>
        </td>
    </tr>
<?php }  ?>

或获取单个用户数据

public function userdetails($user_id) {

    $this->load->model('user_model');

    $user_info = $this->user_model->getUserInfo($user_id);

    $data['user_id'] = $user_info['user_id'];

    $data['username'] = $user_info['username'];

    $this->load->view('profiel_user', $data);

}

查看

或者对于单用户选项

<a href="<?php echo base_url('user/userdetails/' . $user_id);?>"><?php echo $username;?></a>

这篇关于回显用户信息在Codeigniter中不起作用的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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