如何在Codeigniter中获取发出请求的类 [英] How to get the class from which a request originates in codeigniter

问题描述

我的模块全部扩展了Backend控制器，该控制器检查是否已登录并适当地重定向，现在我有了Class FrontEnd [负责登录，注册等页面]，它扩展了My_Controller。
我该如何为FrontEnd创建豁免以使其能够访问模块，因为它需要它们的方法来执行任务。

My modules all extend Backend controller which checks if loggedin and redirects appropriately, now I have Class FrontEnd [responsible for pages like login, signup etc] which extends My_Controller. how can I create an exemption for FrontEnd to be able to access the modules since it needs their methods to perform tasks.

这是我目前拥有的。 ...

this is what I have currently ....

class Backend_Controller extends MY_Controller {

// --------------------------------------------------------------------------
    public function __construct() {
        parent::__construct();
        $this->checkLoggedIn();
    }

// --------------------------------------------------------------------------
    public function checkLoggedIn() {
        //check if loggedin
        if (!$this->auth->loggedIn()) {
            //implement exclusion for FrontEnd class to allow access to methods though not        logged in
            if (!the class trying to access == 'FrontEnd') { //how to get refferal page
                return;
            } else {
                redirect('login');
            }
        }
    }
// --------------------------------------------------------------------------
}

我如何获得尝试访问的类=='FrontEnd
附加信息：
FrontEnd类生成一个表单，该表单的
此处输入代码 action = router-> fetch_class（）将导致someMoudleName，
，但我想要的是它能够检测到该操作来自FrontEnd类

how can I get "the class trying to access == 'FrontEnd" Edditional Info: the FrontEnd class generates a form which has an enter code hereaction= router->fetch_class() will result in someMoudleName , but what i want is for it to be able to detect that the action is coming from FrontEnd Class

推荐答案

这取决于您的网址，但您可以执行以下操作。.

This will depend on your url but u can do something like this..

 function getNameOfOriginatingClass{
     $this->load->library('user_agent');
     $previous_url = $this->agent->referrer();
     $url_segments = explode('/',$previous_url);
     echo '<pre>';print_r($url_segments);    
 }

打印此结果后，您可以看到您的链接分成数组。通常，$ url_segments [3]或$ url_segments [4]将包含您先前的函数名称，而先前的将包含先前的类名称（取决于您的URL）。

after printing this result u can see your link broken into parts in an array.. Normally the $url_segments[3] or $url_segments[4] will contain your previous function name and previous one will contain previous class name depending upon your url.

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