Codeigniter-无法将类__PHP_Incomplete_Class的对象转换为字符串 [英] Codeigniter - Object of class __PHP_Incomplete_Class could not be converted to string

问题描述

当我回显 is_active 变量时，我得到了一个__PHP_Incomplete_Class类的对象无法转换为字符串错误，我可以使用用户名和is_logged_in正常工作变量，但是没有is_active变量，我想知道我在这里可能做错了什么...

I'm getting a Object of class __PHP_Incomplete_Class could not be converted to string error when I echo my is_active variable, I can work just fine with the username and is_logged_in variable, but not with the is_active variable, I'm wondering what I could be doing wrong here...

在我的控制器上，我做了：

On my controller I did:

$username=$this->input->post("username");
            $activated_val=$this->membership_model->is_activated($username);

            $data = array(
                "username" => $this->input->post("username"),
                "is_logged_in" => true,
                "is_active" => $activated_val
            );
            $this->session->set_userdata($data);
            redirect("main");

我的模型函数：

function is_activated($username){
        $query = "SELECT activated FROM members WHERE username=?";
        $result = $this->db->query($query, $username);

        return $result;
    }

在我看来：

$is_active= $this->session->userdata("is_active");
                echo $is_active;

推荐答案

在模型中更改从

In your model change the return line from

return $result;

到

return $result->row()->activated;

查询将CodeIgniter对象传递给<$ c之后，它甚至还不是结果$ c> row（）会得到一个具有数据库列值作为该对象属性的对象，然后通过获取 activated 列值（->已激活）此对象的相应属性。

The query returns a CodeIgniter object which is not even a result yet, after passing it to row() you get an object with your database column values as this object attributes, then you refer to the activated column value by getting(->activated) the corresponding attribute of this object.

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