Codeigniter中的表单操作被添加到现有URL [英] Form Actions in Codeigniter gets added to the existing URL

问题描述

我是Codeigniter的新手，我面临一个小问题。我有一个名为 test的控制器，想在该控制器中调用 edit_details操作。这是我正在开发的测试应用程序。我想更新用户信息，并通过以下URL发送用户ID（URL段）： http：//localhost/codeigniter/index.php/test/edit/12。编辑操作会使用可在其中输入用户详细信息的表单加载视图。这是使用视图中的锚点完成的（每个记录旁边的编辑链接）。锚点： test / edit / $ row-> id。到目前为止，一切都工作正常。

I am new to codeigniter and i am facing a small issue. I have a controller named "test" and would like to call the "edit_details" action within that controller. This is a test application i am developing. I would like to update a user's information and i am sending the user id via(URL segments) the URL: "http://localhost/codeigniter/index.php/test/edit/12" as an example. The edit action loads the view with a form where the user's details could be entered. This is done using an anchor from the view(an edit link next to each record). Anchor: "test/edit/$row->id". Everything so far works great.

问题是，当我使用操作 test / update_details提交表单时，URL变为 http：// localhost / codeigniter /index.php/test/edit/test/update_details'。 edit_details操作加载一个模型，然后该模型执行数据库工作。 ID是使用视图中的隐藏字段发送的。

The problem is when i submit the form with the action 'test/update_details', the url then becomes "http://localhost/codeigniter/index.php/test/edit/test/update_details'". The edit_details action loads a model which then does the database stuff. The id is sent using a hidden field in the view.

我不确定这里出了什么问题。当我调用控制器时，URL似乎没有改变。它要么保持不变，要么附加到现有的URL。我曾尝试谷歌搜索解决方案，但找不到任何。

I am not sure what is going wrong here. The URL doesnt seem to change when i make calls to a controller. It either stays the same or gets appended to the existing URL. I have tried google to search for a solution but couldnt find any.

我仍然没有删除我的index.php，因为这是一个测试应用程序。
配置文件中的基本URL是： http：// localhost / codeigniter /
自动加载的帮助程序是：表单和url
自动加载的库是：数据库

I still havent removed my index.php as this is a test application. My base url in the config file is : "http://localhost/codeigniter/" Autoloaded helpers are: form and url Autoloaded libraries are: database

谢谢。

推荐答案

听起来您需要使用base_url传递回表单（）。
换句话说：

It sounds like you need to pass the form back using the base_url(). In other words:

http://localhost/codeigniter/index.php/test/edit/test/update_details

是错误的。我相信您确实是在尝试将编辑视图详细信息传递给：

is wrong. I believe you are really trying to pass the edit view details to:

http://localhost/codeigniter/index.php/test/update_details

通过提交，您的网址混乱了。
您的form_open应该看起来像这样：

via submit, your url is getting messed up. Your form_open should look like this:

echo form_open(base_url()."test/update_details");

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