如何嘲笑获得(ID)的请求 [英] How to mock get(id) requests
问题描述
我建立一个应用程序的原型,并尝试嘲笑REST的Web服务。
I am building an application prototype and try to mock the REST web-services.
下面是我的code:
var mock = angular.module('mock', ['ngMockE2E']);
mock.run(function($httpBackend){
users = [{id:1,name:'John'},{id:2,name:'Jack'}];
$httpBackend.whenGET('/users').respond(users);
$httpBackend.whenGET(new RegExp('\\/users\\/[0-9]+')).respond(users[0]);
}
一切正常,我的资源User.query()返回所有用户,User.get({ID:1})和User.get({ID:2})。返回相同的用户(约翰)
Everything is ok, my resource User.query() returns all users, and User.get({id:1}) and User.get({id:2}) returns the same user (John).
现在,以提高我的原型,我想回相应的用户,匹配良好的ID。
Now to improve my prototype, I would like to return the appropriate user, matching the good id.
我角文档我应该能够取代正则表达式URI由函数。这个想法是从URL中respond方法用它提取的ID。
然后,我尝试这样的:
I read in the angular documentation I should be able to replace the RegExp URI by a function. The idea is to extract the id from the url to use it in respond method. I then tried this:
$httpBackend.whenGET(new function(url){
alert(url);
var regexp = new RegExp('\\/users\\/([0-9]+)');
id = url.match(regexp)[1];
return regexp.test(url);
}).respond(users[id]);
问题是URL参数总是不确定的。任何想法来实现我的目标?
The problem is the url parameter is always undefined. Any idea to achieve my goal?
推荐答案
我发现了一个解决方案,通过在部分响应,而不是部分时,使用功能:
I found a solution by using a function in the respond part instead of the when part:
$httpBackend.whenGET(new RegExp('\\/users\\/[0-9]+')).respond(
function(method, url){
var regexp = new RegExp('\\/users\\/([0-9]+)');
var mockId = url.match(regexp)[1];
return [200, users[mockId]];
}
});
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