如何在system，exec或shell_exec中运行多个命令？ [英] How to run multiple commands in system, exec or shell_exec?

问题描述

我正在尝试从php运行这样的shell命令：

I'm trying to run shell command like this from php:

ls -a | grep mydir

但是php仅使用第一个命令。有什么方法可以迫使php将整个字符串传递给shell？

But php only uses the first command. Is there any way to force php to pass the whole string to the shell?

（我不在乎输出）

推荐答案

http://www.php.net/manual/zh-CN/function.proc-open.php

首次打开 ls- a 读取输出，将其存储在var中，然后打开 grep mydir 写入您从 ls存储的输出-a 然后再次读取新的输出。

First open ls -a read the output, store it in a var, then open grep mydir write the output that you have stored from ls -a then read again the new output.

LE：

<?php
//ls -a | grep mydir

$proc_ls = proc_open("ls -a",
  array(
    array("pipe","r"), //stdin
    array("pipe","w"), //stdout
    array("pipe","w")  //stderr
  ),
  $pipes);

$output_ls = stream_get_contents($pipes[1]);
fclose($pipes[0]);
fclose($pipes[1]);
fclose($pipes[2]);
$return_value_ls = proc_close($proc_ls);


$proc_grep = proc_open("grep mydir",
  array(
    array("pipe","r"), //stdin
    array("pipe","w"), //stdout
    array("pipe","w")  //stderr
  ),
  $pipes);

fwrite($pipes[0], $output_ls);
fclose($pipes[0]);  
$output_grep = stream_get_contents($pipes[1]);

fclose($pipes[1]);
fclose($pipes[2]);
$return_value_grep = proc_close($proc_grep);


print $output_grep;
?>

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