sed -i选项有什么作用？ [英] What does sed -i option do?

问题描述

我正在调试shell脚本，并试图找出由以下命令执行的任务：

I'm debugging a shell script and trying to find out the task performed by the following command:

sed -i '1,+999d' /home/org_user/data.txt

我需要将此命令更改为失败并显示以下错误：

I need to change this command as its failing with the following error:

illegal option sed -i

但是在进行更改之前，我需要了解BAU的功能。

But before changing, I need to understand the BAU functioning.

在这方面感谢任何投入。 / p>

Appreciate any inputs in this regard.

推荐答案

对此的适用用法如下。假设您有以下文件 file.txt ：

An applicable use of this is as follows. Say you have the following file file.txt:

1, 2, 6, 7, "p" 

我们想将 p替换为0。

We want to replace "p" with 0.

sed 's/"p"/0/g' file.txt

使用上面的命令只是将输出打印到命令行中。

Using the above simply prints the output into command line.

您会想为什么不重定向它呢？像这样将文本返回文件：

You'd think why not just redirect that text back into the file like this:

sed 's/"p"/0/g' file.txt > file.txt

不幸的是，由于重定向的性质，上面只会产生一个空白文件。

Unfortunately because of the nature of redirects the above will simply produce a blank file.

相反，必须为输出创建一个临时文件，稍后将覆盖原始文件，如下所示：

Instead a temp file must be created for the output which later overwrites the original file something like this:

sed 's/"p"/0/g' file.txt > tmp.txt && mv tmp.txt file.txt

而不是在sed上方执行冗长的解决方法-使用-我允许使用更简单的命令：

Instead of doing the long workaround above sed edit in place option with -i allows for a much simpler command:

sed -i 's/"p"/0/g' file.txt

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