xargs的默认分隔符可以更改吗？ [英] Can xargs' default delimiter be changed?

问题描述

我想要以下行为，而不必用选项明确指定它：

I want the following behavior without having to explicitly specify it with options:

xargs -d '\n'

与大多数命令不同，您不能仅使用别名，因为管道无法识别别名（如旁注，为什么要这样设计？）。我也尝试过创建自己的〜/ bin / xargs 脚本，但我认为它不像在脚本中读取字符串那样简单地读取 $ @。

Unlike with most commands, you can't just use an alias because pipes don't recognize aliases (as a side-note, why is it designed this way?). I also tried creating my own ~/bin/xargs script but I think it's not as simple as reading "$@" as a string inside the script.

任何建议如何使分隔符默认为换行符？当路径中有空格时，我不想出现很多错误（并且使用 find ... -print0 | xargs -0 还有其他不良影响） 。

Any suggestions how to make the delimiter a newline by default? I don't want to get a bunch of errors when I have a space in the path (and using find ... -print0 | xargs -0 has other unwanted effects).

更新

我的shell脚本尝试是这样的：

My shell script attempt is this:

/usr/local/bin/xargs -d '\n' "$@"

推荐答案

我测试了 xargs -d'\n'-n1 echo 在命令行上，并且按宣传的方式工作；

I tested xargs -d '\n' -n1 echo on the command line and it worked as advertised; breaking the input up into single lines and echoing it.

您可能会因变量分配过程中外壳转义的假设而感到困惑。例如，如果您的Shell脚本与此类似：

You could be being bitten by assumptions regarding shell escaping during variable assignment. For instance, if your shell script is similar to this:

CMD = xargs -d'\n'-n1 echo

cat输入文件| $ CMD

CMD="xargs -d '\n' -n1 echo"
cat inputfile | $CMD

然后会发生错误，因为整个CMD字符串周围的双引号保留了单引号和反斜杠分隔符。

then an error occurs, because the double-quotes around the entire CMD string preserve both the single-quotes and the backslash in the delimiter.

如果将xargs命令括在引号中，则可以将其更改为以下内容（无单引号）

If you are enclosing the xargs command within quotes, you could change it to the following (no single-quotes)

CMD = xargs -d \n -n1 echo

cat输入文件| $ CMD

CMD="xargs -d \n -n1 echo"
cat inputfile | $CMD

，它可能会根据您的需要起作用。

and it will likely function as you need.

经过测试在CentOS 6.4，xargs版本4.4.2

Tested on CentOS 6.4, xargs version 4.4.2

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