如何在WinDbg的启动命令行中打开转储符时转义引号 [英] How to escape quotation marks in WinDbg's startup command line opening a dump

问题描述

遵循此答案，我正在尝试使用 -c ... .dmp shell命令$ c>打开我的转储文件时执行命令。

Following this answer, I'm trying to set up a .dmp shell command in the Registry using the -c "..." switch to execute commands whenever I open a dump file.

尽管此方法适用于任何不使用引号的命令，但我现在想使用需要引号的命令。我如何才能避免引号引起来，以使它们不被视为 -c ... 开关的结尾？

While this works for any commands not using quotation marks, I'd now like to use a command which needs quotation marks. How can I escape the quotation marks to that they are not seen as the end of the -c "..." switch?

我尝试过：

• 使用反斜杠 \


• 通过加引号



• escaping with a backslash \"
• escaping by doubling the quotation marks ""

详细信息如下：

注册表项： HKEY_CLASSES_ROOT\Windbg.DumpFile.1\shell\WinDbgStartup\command

（默认值）（工作）： C：\windbg.exe的路径 -z ％1 -Q -c .echo欢迎

(Default) value (working): "C:\path to\windbg.exe" -z "%1" -Q -c ".echo Welcome"

（默认）值（断开）： C：\windbg.exe的路径 -z％1 -Q -c .echo Wel来

(Default) value (broken): "C:\path to\windbg.exe" -z "%1" -Q -c ".echo Wel""come"

-z 用于打开转储文件， -Q 用于安静的工作空间，位于 -c 我可以输入命令，并且要包含引号。

-z is for opening a dump file, -Q is for quiet workspaces, at -c I can enter commands and I want to include quatation marks.

错误消息：命令行参数不能指定一种以上的调试来启动

WinD bg版本： 6.2.9200.16384 X86

WinDbg Version: 6.2.9200.16384 X86

推荐答案

您是否尝试过 ^ ？ ^ 转义了 cmd

Have you tried ^" ? ^ escapes most characters in cmd

（正在调查）

从 WinDbg命令行选项

-c " command "

    Specifies the initial debugger command to run at start-up. This command must be 
    enclosed in quotation marks. Multiple commands can be separated with semicolons. 
    (If you have a long command list, it may be easier to put them in a script and 
    then use the -c option with the $<, $><, $><, $$>< (Run Script File) command.)

    If you are starting a debugging client, this command must be intended for the 
    debugging server. Client-specific commands, such as .lsrcpath, are not allowed.

然后单击 $ ... 超链接进一步解释了这些选项。

And clicking on the $... hyperlink further explains these options.

似乎您实际上想在 echo $ c>。坦率地说，我不知道-但是我要尝试的是 -c .echo Wel ^ come

，如果那不起作用，我将转到 $-option gobbledegook。没有人（理智的）声称在建造这些设施时已经考虑了所有可能性...

and if that doesn't work, I'd go off to the $-option gobbledegook. No-one (sane) ever claimed that every possibility had been considered in constructing these facilities...

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