PHP session_start函数和CLI [英] PHP session_start function and CLI

问题描述

PHP CLI中使用的函数session_start打印下一条警告： session_start（）：无法发送会话cookie-已发送的标头（输出始于/home/robi/p/test.php:1）在/home/robi/p/test.php的第2行上为什么？

Function session_start used in PHP CLI print the next warning: session_start(): Cannot send session cookie - headers already sent by (output started at /home/robi/p/test.php:1) in /home/robi/p/test.php on line 2 why?

我想将所有客户端条目记录到变量中，并检查到通过比较用户的上次进入时间和当前进入时间，看看我是否从特定的远程地址得到了伪造品！

I want to log all the client entries in a variable and check this out to see if i get forgery from a specific remote address by comparing the time user last entry and current entry time! Am I doing it wrong?

这是我的代码吗？

<?php 
session_start();
$client_entry = time();
$_SESSION["entries"][] =  $client_entry;
$entries = $_SESSION["entries"];


$check_out = array_filter(
    $entries,
    function($value) use($client_entry) {
        return ($value >= ($client_entry + (1 * 0.6)));
    }
);

推荐答案

您的问题是，除此之外，这毫无意义要在CLI中使用会话，该输出已经在 session_start（）; 之前开始。

Your problem is, apart from that it makes no sense to use sessions in CLI, that output has already started prior to session_start();.

您的代码，您的代码直接以 session_start（）; 开头，我相信您在<？php 之前有一些字符。确保<？php 位于文件的第一行（因此文件上方也没有空行），并且没有任何内容（例如空格）

As I see in your code, you code begins directly with session_start();, I believe you have some characters before <?php. Make sure <?php is on the very first line of your file (so also no empty lines above it), and that there is nothing (such as a white space) in front of it.

这应该可以解决您遇到的这个问题。

This should fix this problem you are having.

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