SQL Server 2008 CTE递归 [英] SQL Server 2008 CTE Recursion
问题描述
我正在尝试执行我认为使用CTE进行递归比较困难的操作是SQL Server2008。我似乎无法将这个问题包扎起来。
I am trying to perform what I believe is a difficult recursion using a CTE is SQL Server 2008. I can't seem to wrap my head around this one.
在下面的示例中,您可以假设固定深度为3 ...没有任何比这更低的深度了。在现实生活中,深度是更深的,但仍然是固定的。在示例中,我尝试将其简化。
In the below examples you can assume a fixed depth of 3...nothing will ever be lower than that. In real life, the depth is "deeper" but still fixed. In the example I tried to simplify it some.
我的输入数据如下所示。
My input data is like the below.
ID PARENT_ID NAME DEPTH
------------------------------------------
1 NULL A 1
2 1 B 2
3 2 C 3
4 1 D 2
我的CTE输出应为下表。
The output of my CTE should be the following table.
LEVEL1_ID LEVEL2_ID LEVEL3_ID LEVEL1_NAME LEVEL2_NAME LEVEL3_NAME
--------------------------------------------------------------------------------
1 NULL NULL A NULL NULL
1 2 NULL A B NULL
1 2 3 A B C
1 4 NULL A D NULL
如果我可以在输出中获取ID列,则可以肯定地映射到查找表中的名称。
If I can get the ID columns in the output I can certainly map to names in a lookup table.
我是
推荐答案
并不是很困难:
;WITH cte AS
(
SELECT CAST('/' + Name AS VARCHAR(50)) as 'CteName', ID
FROM dbo.YourTable
WHERE parent_id IS NULL
UNION ALL
SELECT CAST(cte.CteName + '/' + Name AS VARCHAR(50)), t.ID
FROM dbo.YourTable t
INNER JOIN cte ON t.parent_id = cte.id
)
SELECT cteName FROM cte
ORDER BY ID
为我提供以下输出:
/A
/A/B
/A/B/C
/A/D
作为旁注:深度可由CTE轻松计算,您不一定需要将其存储在表中(请参阅我添加的级别
列d):
As a side-note: the "depth" could be easily computed by the CTE and you don't necessarily need to store that in your table (see the Level
column I've added):
;WITH cte AS
(
SELECT
CAST('/' + Name AS VARCHAR(50)) as 'CteName', ID,
1 AS 'Level'
FROM dbo.YourTable
WHERE parent_id IS NULL
UNION ALL
SELECT
CAST(cte.CteName + '/' + Name AS VARCHAR(50)), t.ID,
cte.Level + 1 AS 'Level'
FROM dbo.YourTable t
INNER JOIN cte ON t.parent_id = cte.id
)
SELECT cteName FROM cte
ORDER BY Level, ID
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