父文件夹中的phpʻuse`类 [英] php `use` class in parent folder
问题描述
我已经使用推进ORM nofollow> Composer ,但我无法创建新模型,因为PHP脚本与PHP类不在同一目录中。
I have installed Propel ORM with Composer but I cannot create a new model as the PHP script is not in the same directory as the PHP class.
我在 Test.php
内有类 Test
我想从 subfolder / index.php
使用它。请注意,类 Test
然后使用 Base / Test.php $中的
Base / Test
c $ c>,因此在这里不能使用 require()
,因为 Base / Test
可以继续使用作曲家生成的更多类。
I have class Test
inside Test.php
and I want to use it from subfolder/index.php
. Note that class Test
then uses Base/Test
from Base/Test.php
, so using require()
is not an option here as Base/Test
just goes on to use even more classes generated by composer.
传统上,我应该执行以下操作:
Traditionally, I'm supposed to do the following:
<?php
use Test;
?>
但是由于我的父母有 Test
文件夹,我无法做到这一点,显然
but since I have Test
in the parent folder, I cannot do that, and obviously
<?php
use ../Test;
?>
不起作用。
我的文件夹结构:
My Project
|-- Base
| `-- Test.php <-- File referenced by `Test` class
|-- subfolder
| `-- index.php <-- File I want to use `Test` from
`-- Test.php <-- File containing `Test` class
实际代码:
子文件夹/index.php
:
<?php
use \Test;
require __DIR__ . '/../vendor/autoload.php';
$test = new Test();
?>
Test.php
:
<?php
use Base\Test as BaseTest;
class Test extends BaseTest
{
}
推荐答案
Test
是一个命名空间,实际上与文件夹结构无关。命名空间具有类似于 的文件夹结构,但是您不能使用相对路径。
Test
is a namespace and has literally nothing to do with folder structure. Namespaces have a folder-like structure, but you cannot use relative paths.
PSR-4自动加载器,例如大多数Composer软件包都使用它们几天以来,以与文件夹结构非常匹配的方式映射它们的名称空间,但它们仍然是完全独立的概念。
PSR-4 autoloaders, such as what most Composer packages use these days, map their namespaces in a way that very closely matches the folder structure, but they are still entirely separate concepts.
如果已声明文件中的名称空间,所有后续名称都被认为是相对于该路径的。例如:
If you have declared a namespace in a file all subsequent names are considered to be relative to that path. eg:
namespace Foo;
class Bar {}; // \Foo\Bar
如果要在外部使用 当前名称空间中的>,您需要声明完整路径,以 \
开头,该路径表示 root 名称空间。例如:
If you want to use something outside of the current namespace you need to declare the full path, beginning with \
which signifies the root namespace. eg:
namespace Foo;
use \Test
class Bar { // \Foo\Bar
public function test() {
$test = new Test();
$dbh = new \PDO();
}
}
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