凹壳实现 [英] Concave Hull implementation
问题描述
我正在尝试实施以下 http://repositorium.sdum.uminho.pt/bitstream/1822/6429/1/ConcaveHull_ACM_MYS.pdf
我正在使用以下类库。 Loyc库来自 http://core.loyc.net/
I am using the following class libraries. Loyc libs come from http://core.loyc.net/
using System;
using System.Collections.Generic;
using System.Linq;
using System.Device.Location;
using Loyc.Collections;
using Loyc.Geometry;
using Loyc;
这是基本课程
public class Hulls
{
private static List<Point<double>> KNearestNeighbors(List<Point<double>> points, Point<double> currentPoint, int k, out int kk)
{
kk = Math.Min(k, points.Count - 1);
var ret = points
.OrderBy(x => PointMath.Length(new Vector<double>(currentPoint.X - x.X, currentPoint.Y - x.Y)))
.Take(k)
.ToList();
return ret;
}
private static double Angle(Point<double> a, Point<double> b)
{
var ret = -Math.Atan2(b.Y - a.Y, b.X - a.X);
return NormaliseAngle(ret);
}
private static double NormaliseAngle(double a)
{
//while (a < b - Math.PI) a += Math.PI * 2;
//while (b < a - Math.PI) b += Math.PI * 2;
if (a < 0.0) { return a + Math.PI + Math.PI; }
return a;
}
private static List<Point<double>> SortByAngle(List<Point<double>> kNearest, Point<double> currentPoint, double angle)
{
//kNearest
// .Sort((v1, v2) => AngleDifference(angle, Angle(currentPoint, v1)).CompareTo(AngleDifference(angle, Angle(currentPoint, v2))));
//return kNearest.ToList();
kNearest = kNearest.OrderByDescending(x => NormaliseAngle(Angle(currentPoint, x) - angle)).ToList();
return kNearest;
}
private static bool CCW(Point<double> p1, Point<double> p2, Point<double> p3)
{
var cw = ((p3.Y - p1.Y) * (p2.X - p1.X)) - ((p2.Y - p1.Y) * (p3.X - p1.X));
return cw > 0 ? true : cw < 0 ? false : true; // colinear
}
private static bool _Intersect(LineSegment<double> seg1, LineSegment<double> seg2)
{
return CCW(seg1.A, seg2.A, seg2.B) != CCW(seg1.B, seg2.A, seg2.B) && CCW(seg1.A, seg1.B, seg2.A) != CCW(seg1.A, seg1.B, seg2.B);
}
private static bool Intersect(LineSegment<double> seg1, LineSegment<double> seg2)
{
if ((seg1.A.X == seg2.A.X && seg1.A.Y == seg2.A.Y)
|| (seg1.B.X == seg2.B.X && seg1.B.Y == seg2.B.Y))
{
return false;
}
if (_Intersect(seg1, seg2))
{
return true;
}
return false;
}
public IListSource<Point<double>> KNearestConcaveHull(List<Point<double>> points, int k)
{
points.Sort((a, b) => a.Y == b.Y ? (a.X > b.X ? 1 : -1) : (a.Y >= b.Y ? 1 : -1));
Console.WriteLine("Starting with size {0}", k.ToString());
DList<Point<double>> hull = new DList<Point<double>>();
var len = points.Count;
if (len < 3) { return null; }
if (len == 3) { return hull; }
var kk = Math.Min(Math.Max(k, 3), len);
var dataset = new List<Point<double>>();
dataset.AddRange(points.Distinct());
var firstPoint = dataset[0];
hull.PushFirst(firstPoint);
var currentPoint = firstPoint;
dataset.RemoveAt(0);
double previousAngle = 0;
int step = 2;
int i;
while ((currentPoint != firstPoint || step == 2) && dataset.Count > 0)
{
if (step == 5) { dataset.Add(firstPoint); }
var kNearest = KNearestNeighbors(dataset, currentPoint, k, out kk);
var cPoints = SortByAngle(kNearest, currentPoint, previousAngle);
var its = true;
i = 0;
while (its == true && i < cPoints.Count)
{
i++;
int lastPoint = 0;
if (cPoints[i - 1] == firstPoint)
{
lastPoint = 1;
}
int j = 2;
its = false;
while (its == false && j < hull.Count - lastPoint)
{
LineSegment<double> line1 = new LineSegment<double>(hull[step - 2], cPoints[i - 1]);
LineSegment<double> line2 = new LineSegment<double>(hull[step - 2 - j], hull[step - 1 - j]);
//its = LineMath.ComputeIntersection(line1, line2, out pfrac, LineType.Segment);
its = Intersect(line1, line2);
j++;
}
}
if (its == true)
{
return KNearestConcaveHull(points, kk + 1);
}
currentPoint = cPoints[i - 1];
hull.PushLast(currentPoint);
previousAngle = Angle(hull[step - 1], hull[step - 2]);
dataset.Remove(currentPoint);
step++;
}
bool allInside = true;
i = dataset.Count;
while (allInside == true && i > 0)
{
allInside = PolygonMath.IsPointInPolygon(hull, dataset[i - 1]);
i--;
}
if (allInside == false) { return KNearestConcaveHull(points, kk + 1); }
return hull;
}
}
以上内容应该为边界基于从上一个边缘向右逆时针旋转最远的角度。该代码似乎从初始顶点中选取了具有y值最低的正确的第一条边，但是当偏移角度为非零时，然后没有正确地选择下一条边。我认为问题是SortByAngle或Angle。 -atan2将返回顺时针旋转，对吗？
The above is supposed to pick a new edge for the boundary based on the furthest right-hand turn from the previous edge going around the point set counterclockwise. The code seems to pick the correct first edge from the initial vertex which has the lowest y-value, but then does not pick the next edge correctly when the offset angle is nonzero. I think the issue is the SortByAngle or Angle. -atan2 would return the clockwise turn, correct? Possibly I should be adding the offset angle?
编辑（解决方案）：在按照问题的第一条评论中Eric的有用建议后，发现了问题。这是SortByAngle和Angle：
EDIT (SOLUTION): Found the issue after following Eric's helpful advice provided in the first comment to the question. It was SortByAngle and Angle:
private static double Angle(Point<double> a, Point<double> b)
{
var ret = Math.Atan2(b.Y - a.Y, b.X - a.X);
return NormaliseAngle(ret);
}
private static double NormaliseAngle(double a)
{
if (a < 0.0) { return a + Math.PI + Math.PI; }
return a;
}
private static List<Point<double>> SortByAngle(List<Point<double>> kNearest, Point<double> currentPoint, double angle)
{
//kNearest = kNearest.OrderByDescending(x => NormaliseAngle(Angle(currentPoint, x) - angle)).ToList();
kNearest.Sort((a, b) => NormaliseAngle(Angle(currentPoint, a) - angle) > NormaliseAngle(Angle(currentPoint, b) - angle) ? 1 : -1);
return kNearest;
}
推荐答案
您有一些错误：
var kNearest = KNearestNeighbors(dataset, currentPoint, k, out kk);
将kk更改为一些变量。覆盖该 kk值的增量，然后得到StackOverflow异常。
Change the kk to just some var. You override the incrementation of that "kk" value, and then you're getting StackOverflow exceptions.
将代码更改为以下内容：
Change your code to the following:
int someVal;
var kNearest = KNearestNeighbors(dataset, currentPoint, k, out someVal);
这篇关于凹壳实现的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
