如何显示/隐藏控制台窗口应用程序？ [英] How to show/hide a console window app?

问题描述

我有一个小型控制台应用程序。当我从主程序中调用它时，我想隐藏它的窗口（使用-hide作为命令行参数），并在用户启动它时显示它的窗口（没有命令行参数）。

I have a small console app. I want to hide its window when it is called from my main program (with -hide as command line parameter) and show it when the user starts it (no command line param).

此问题建议使用{$ APPTYPE GUI}而不是{$ APPTYPE CONSOLE}将隐藏窗口。确实有效。但是，当用户运行时，如何使窗口可见？

This question suggests that using {$APPTYPE GUI} instead of {$APPTYPE CONSOLE} will hide the window. And indeed it works. But how do I make the window visible when ran by user?

目的：我希望我的主程序在后台与控制台应用程序进行静默交互（控制台不可见） 。因此，当用户单独启动控制台应用程序时，我只想向他发出警告：‘该控制台应用程序正在执行x任务。您无法手动启动它。

Purpose: I want my main program to interact with the console app silently in the background (console is invisible). So, when the user starts the console app alone, I just want to give him a warning: 'This console app is doing x task. You cannot start it manually'.

推荐答案

1. 将程序作为控制台应用程序保留下来。不要将其放入GUI应用程序中，因为这意味着用户直接启动它时，将不会获得控制台。


2. 从主应用程序启动程序时，请使用 CreateProcess 为此，传递 CREATE_NO_WINDOW 标志。该标志确保不会创建任何控制台窗口。

1. Leave the program alone, as a console application. Do not make it into a GUI application because that means that when users start it directly, it will not be given a console.
2. When you start the program from your main app, use CreateProcess to do so, passing the CREATE_NO_WINDOW flag. That flag ensures that no console window will be created.

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