使用未定义的常数 [英] Use of undefined constant
问题描述
我在我的网站
中遇到此错误我的网站是wordpress 4
i使用发布格式
以发布格式我创建了这个php,如果页面有引用发布,则不要加载标题和图像等来自报价单的内容只是显示报价内容是meta框(wordpress)
Hi I have this error in my website my website is wordpress 4 i use post format in post format i create this php to if page has quote post then dont load title and image and etc from quote post just show quote content is meta box (wordpress)
Notice: Use of undefined constant quote - assumed 'quote' in C:\xampp\htdocs\personal\wp-content\themes\personal\warp\systems\wordpress\layouts\_post.php on line 4
和
Notice: Use of undefined constant quote - assumed 'quote' in C:\xampp\htdocs\personal\wp-content\themes\personal\warp\systems\wordpress\layouts\_post.php on line 14
这是下面的_post.php代码
this is _post.php code in bellow
<?php $format = get_post_format(); ?>
<article id="post-<?php the_ID(); ?>" <?php post_class('group'); ?>>
<?php
if ($format != quote ) {
$css_class = "b-box";
} else {
$css_class = "q-box";
}
echo "<div class=\"$css_class\">";
?>
<?php get_template_part('inc/post-formats'); ?>
<?php if ($format != quote ) : ?>
<div class="post-content">
<div class="blog-img-box">
<img src="<?php echo catch_that_image() ?>" alt="<?php the_title(); ?>" />
</div>
<div class="post-deco blog-icon-box">
<div class="hex hex-small">
<i class="fa blog-icon"></i>
<?php if ( $format != false ) :?><a href="<?php echo get_post_format_link($format); ?>"></a><?php endif; ?>
</div>
</div><!--/.post-deco-->
<h2 class="blog-title">
<a href="<?php the_permalink(); ?>" rel="bookmark" title="<?php the_title(); ?>"><?php the_title(); ?></a>
</h2><!--/.post-title-->
<div class="blog-details row">
<div class="col-md-4"><i class="fa fa-calendar blog-details-icons"></i>
<p class="blog-details-icons-txt"><?php the_time('j M, Y'); ?></p>
</div>
<div class="col-md-4">
<a href="<?php comments_link(); ?>">
<i class="fa fa-comment blog-details-icons"></i>
<p class="blog-details-icons-txt"><?php comments_number( '0', '1', '%' ); ?> Comments</p></a>
</div>
<div class="col-md-4"><i class="fa fa-eye blog-details-icons"></i>
<p class="blog-details-icons-txt"><?php echo getPostViews(get_the_ID()); ?></p>
</div>
<div class="likes"><i class="fa fa-heart blog-details-icons"></i>
<p class="blog-details-icons-txt">18</p>
</div>
</div>
<div class="blog-txt">
<?php the_excerpt(); ?>
</div>
<a href="<?php the_permalink(); ?>" rel="bookmark" title="<?php the_title(); ?>"><div class="readmore-box"><p class="readmore-txt"><?php _e('Read More','anew'); ?></p></div></a>
</div><!--/.post-content-->
<?php endif ?>
</div><!--/.post-inner-->
</article><!--/.post-->
请检查并告诉我我错了
谢谢!
推荐答案
如果要使用报价
作为文字字符串(第4行),而不是变量名,必须将其括在单引号或双引号字符('
或
If you want to use the quote
as a literal string (line 4), not a variable name, you must enclose it into single or double quote characters ('
or "
). Otherwise, PHP thinks that you're referencing a PHP constant.
出于向后兼容的原因,PHP退回了使用字符串作为原义的方法。 ,但确实会引发 E_NOTICE
错误-您遇到的错误。
For reasons of backward compatibility, PHP falls back on using the string as literal, but it does throw an E_NOTICE
error – the one you're experiencing.
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