在代码中获取上下文菜单的所有者 [英] Get owner of context menu in code

查看:45
本文介绍了在代码中获取上下文菜单的所有者的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个像这样的 ContextMenu

<StackPanel Orientation="Horizontal">
    <StackPanel.ContextMenu>
        <ContextMenu>
            <MenuItem Header="Delete" Click="OnDeleteClicked" />
        </ContextMenu>
    </StackPanel.ContextMenu>
</StackPanel>

我需要获取 StackPanel ContextMenu 的c>。我已经尝试过:

And I need to get the instance of the StackPanel that owns that ContextMenu. I already tried this:

private void OnDeleteClicked(object sender, System.Windows.RoutedEventArgs e)
{
    FrameworkElement parent = e.OriginalSource as FrameworkElement;

    while (!(parent is StackPanel))
    {               
        parent = (FrameworkElement)LogicalTreeHelper.GetParent(parent);
    }
}

但是在获取 ContextMenu之后弹出父级,它为null,与 VisualTreeHelper 相同,在获取 StackPanel 。知道如何执行此操作吗?

But after getting the ContextMenu Popup parent, it gets null, same with the VisualTreeHelper, it gets to null before getting the StackPanel. Any idea on how to do this?

谢谢!

推荐答案

这将为您提供所需的确切内容

this will give you the exact thing you want

private void OnDeleteClicked(object sender, System.Windows.RoutedEventArgs e)
{
    MenuItem mnu = sender as MenuItem;
    StackPanel sp = null;
    if(mnu!=null)
    {
        sp = ((ContextMenu)mnu.Parent).PlacementTarget as StackPanel;
    }
}

希望这会有所帮助!

这篇关于在代码中获取上下文菜单的所有者的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆