如何未被授权时，重发请求 [英] How to resend request when not authorized

问题描述

我实现authInterceptorService所以当响应没有授权我送请求新的令牌，然后我要重新发送previoes请求。所以，我需要存储在某个地方，然后重新发送，什么是做的最好的方法是什么？

  VAR _responseError =功能（拒绝）{
        如果（rejection.status === 401）{
            变种authService = $ injector.get（'authService'）;
            变种的authData = localStorageService.get（'authorizationData'）;            如果（的authData）{
                authService.refreshToken（）。然后（功能（响应）{
                        //重定向到原来的请求
                    }，
                 功能（错误）{
                     $ location.path（'/登录'）;
                 }）;
            }            authService.logOut（）;
            $ location.path（'/登录'）;
        }
        返回$ q.reject（拒绝）;
    }
 

解决方案

为什么不把它作为自己的要求呢？

  //定义原始请求
VAR originalRequest =功能（一些输入）{
    $ http.post（URL，数据）。然后（的onSuccess，_responseError）;
}
 

然后在您的_responseError功能，只需调用原始请求

  VAR _responseError =功能（拒绝）{
        如果（rejection.status === 401）{
            变种authService = $ injector.get（'authService'）;
            变种的authData = localStorageService.get（'authorizationData'）;            如果（的authData）{
                authService.refreshToken（）。然后（功能（响应）{
                        //重定向到原来的请求                        originalRequest（一些输入）;                    }，
                 功能（错误）{
                     $ location.path（'/登录'）;
                 }）;
            }            authService.logOut（）;
            $ location.path（'/登录'）;
        }
        返回$ q.reject（拒绝）;
    }
 

此外，失败，你得到请求的原始配置，所以你可以只使用...

 如果（的authData）{
                authService.refreshToken（）。然后（功能（响应）{
                        //重定向到原来的请求                        $ http.post（rejection.config）。然后（...，...）;                    }，
                 功能（错误）{
                     $ location.path（'/登录'）;
                 }）;
            }
 

I implemented authInterceptorService so when response is not authorize I send request for new token and then I want to resend previoes request. So I need to store it somewhere and resend, what is best way to do it?

var _responseError = function (rejection) {
        if (rejection.status === 401) {
            var authService = $injector.get('authService');
            var authData = localStorageService.get('authorizationData');

            if (authData) {
                authService.refreshToken().then(function (response) {
                        //redirect to original request


                    },
                 function (err) {
                     $location.path('/login');
                 });
            }

            authService.logOut();
            $location.path('/login');
        }
        return $q.reject(rejection);
    }

解决方案

Why not make it its own request?

// define the original request
var originalRequest = function( some input ){
    $http.post( 'url' , data ).then(onSuccess, _responseError);
}

then in your _responseError function, just call the original request

var _responseError = function (rejection) {
        if (rejection.status === 401) {
            var authService = $injector.get('authService');
            var authData = localStorageService.get('authorizationData');

            if (authData) {
                authService.refreshToken().then(function (response) {
                        //redirect to original request

                        originalRequest( some input );

                    },
                 function (err) {
                     $location.path('/login');
                 });
            }

            authService.logOut();
            $location.path('/login');
        }
        return $q.reject(rejection);
    }

Also, on failure, you do get the original configuration of the request, so you could just use that...

            if (authData) {
                authService.refreshToken().then(function (response) {
                        //redirect to original request

                        $http.post(rejection.config).then( ... , ... );

                    },
                 function (err) {
                     $location.path('/login');
                 });
            }

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