正则表达式替换转义字符串中的模式控制字符 [英] Regex replace pattern control characters in escaped string
问题描述
我有一个转义的字符串，其中包含某些控制字符。
控制字符是 ACK ， STX 类型。
参考： http://ascii.cl/control-characters.htm
I have an escaped string that contains certain control characters.
The control characters are the ACK, STX types.
Reference: http://ascii.cl/control-characters.htm
我需要用〜替换所有控制字符，最好是所有连续的控制字符。
I need to replace all the control characters, preferably all consecutive control characters with ~.
例如输入
%00%00%00%02THE%20QUICK%BROWN%00%00%00%0D%00%00%00%0FFOX%20JUMPED%00%00%00%0EOVER%20THE%00%00%4E%02LAZY%20DOG
我想要的输出应该是：
~THE%20QUICK%20BROWN~FOX%20JUMPED~OVER%20THE~LAZY%20DOG
为了我自己和其他人，我寻找的方法是替换一个模式这种情况类似于％0？％0？％0？％0 ??
For the sake of myself and others the method i look for is to replace a pattern which in this case would be something like %0?%0?%0?%0?? Meaning anything that could creep into the text.
字符串模式
-
字符串的长度应为12
String should be of length 12
字符串应包含4个百分比的零符号，例如。 ％0
String should contain 4 percentage zero symbols ex. %0
我也欢迎其他建议
目的是摆脱字符串中的所有控制字符。替换为〜只是为了保持在哪里替换（调试）的选项卡。
Intention is to get rid of all control characters from the string. Replacing with ~ is just to keep a tab on what got replaced where (debugging).
推荐答案
尝试以下表达式：
(%[0-13-9A-F][0-9A-F])+
它找到重复的控制字符序列，除了％20。
It finds all sequences of control chars repeated, except for %20.
有了它，我得到以下输出：
With it I get this output:
~THE%20QUICK%BROWN~FOX%20JUMPED~OVER%20THE~LAZY%20DOG
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