Python字符串计数不能正常工作？ [英] Python string count not working properly?

问题描述

在'ababa'中出现了'aba'两次（第0个索引和第2个索引）：

There are two occurrences of 'aba' in 'ababa' (0th index and 2nd index):

myString = 'ababa'
print(myString.count('aba'))

此代码输出值：1

我知道这个问题似乎很简单，但是答案不应该是2吗？

如果不是，那么count函数不是真的在做吗应该怎么办？

Yet this code outputs a value of: 1
I know this issue seems really simple, but shouldn't the answer be 2 here?
If not, then isn't the count function not really doing what it's supposed to?

有没有简单的选择？

推荐答案

从 Python字符串函数文档

返回范围[start，end]中子字符串sub的不重叠的次数。可选参数start和end以切片符号的形式解释。

Return the number of non-overlapping occurrences of substring sub in the range [start, end]. Optional arguments start and end are interpreted as in slice notation.

count 可以

如果要计算重复出现的次数，则可以将正则表达式与前瞻性断言一起使用：

If you want to count overlapping occurrences you can use regex with a lookahead assertion:

import re
print(len(re.findall('(?=aba)', 'ababa')))

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