数字柜台游戏 [英] Number counter game
本文介绍了数字柜台游戏的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试制作一个使用for循环打印6个随机数1-6的随机数计数器游戏。我想这样做,以便代码可以说出数字6在循环中显示了多少次。
目前,我有打印出来的代码,可以循环显示6个随机数,但它只计算打印出的数字。
例如
欢迎来到骰子游戏!
您将滚动多少个六度?
4 2 4 6 4 6
您掷了2个6个!
<?php
echo< h1>欢迎来到猜猜游戏事物猜猜多少6s!< / h1>;
$ counter = 0;
for($ i = 0; $ i< = 6; $ i ++){
$ randomNum = rand(1,6);
if($ randomNum< = 6){
echo< br> $ randomNum;
$ counter ++;
}
else
{
echo $ randomNum< br>;
}
}
echo< br>您滚动了$ counter sixes;
解决方案
您可以这样做:
$ num = $ _POST [ num];
for($ i = 0; $ i< = 100; $ i ++){
$ randomNum = rand(1,10);
if($ randomNum == $ num){
echo $ randomNum;
休息时间;
}
echo $ randomNum;
}
echo< h2>有$ i< / h2>;
Im trying to make a random number counter game that uses a for loop to print out 6 random numbers 1 - 6. I want to make it so the code can say how many times the number 6 shows in the loop.
At the moment I have the code it prints out for a loop of 6 random numbers but it only counts the numbers printed out.
For example Welcome to the Dice Game! How many sixes will you roll? 4 2 4 6 4 6 You rolled 2 six(es)!
<?php
echo"<h1>Welcome to the guess game thing guess how many 6s!</h1>";
$counter = 0;
for ($i=0; $i <=6;$i++) {
$randomNum = rand(1,6);
if ($randomNum <= 6) {
echo "<br> $randomNum";
$counter++;
}
else
{
echo"$randomNum <br>";
}
}
echo"<br>You rolled $counter sixes";
解决方案
You can do it like this:
$num = $_POST["num"];
for ($i=0; $i <=100;$i++) {
$randomNum = rand(1,10);
if ($randomNum == $num) {
echo $randomNum;
break;
}
echo $randomNum;
}
echo"<h2> there are $i</h2>";
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