Linux中进程的CPU争用（等待时间） [英] CPU contention (wait time) for a process in Linux

问题描述

如何检查一个进程在Linux机器中等待CPU的时间？

How can I check how long a process spends waiting for the CPU in a Linux box?

例如，在一个加载的系统中，我想检查一个 SQL * Loader （sqlldr）进程正在等待。

For example, in a loaded system I want to check how long a SQL*Loader (sqlldr) process waits.

如果有命令行工具可以执行此操作。

It would be useful if there is a command line tool to do this.

推荐答案

我遇到了这个问题回来一段时间我最终使用getrusage：
您可以在以下位置获得详细的帮助：
http://www.opengroup.org/onlinepubs/009695399/functions/getrusage.html

I had this problem some time back. I ended up using getrusage : You can get detailed help at : http://www.opengroup.org/onlinepubs/009695399/functions/getrusage.html

getrusage填充了rusage结构。

getrusage populates the rusage struct.

使用getrusage测量等待时间

您可以在代码的开头调用getrusage，然后在代码结尾或执行过程中的某个适当时间再次调用它。然后，您将拥有initial_rusage和final_rusage。您的进程花费的用户时间由rusage-> ru_utime.tv_sec指示，而该进程花费的系统时间由rusage-> ru_stime.tv_sec指示。

You can call getrusage at the beginning of your code and then again call it at the end, or at some appropriate point during execution. You have then initial_rusage and final_rusage. The user-time spent by your process is indicated by rusage->ru_utime.tv_sec and system-time spent by the process is indicated by rusage->ru_stime.tv_sec.

因此，该流程花费的总用户时间为：
user_time = final_rusage.ru_utime.tv_sec-initial_rusage.ru_utime.tv_sec

Thus the total user-time spent by the process will be: user_time = final_rusage.ru_utime.tv_sec - initial_rusage.ru_utime.tv_sec

该流程花费的总系统时间为：
system_time = final_rusage.ru_stime.tv_sec-initial_rusage.ru_stime.tv_sec

The total system-time spent by the process will be: system_time = final_rusage.ru_stime.tv_sec - initial_rusage.ru_stime.tv_sec

如果total_time是两次调用getrusage之间的时间，则等待时间为
wait_time = total_time-（user_time + system_time）

If total_time is the time elapsed between the two calls of getrusage then the wait time will be wait_time = total_time - (user_time + system_time)

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