PHP Cron Job：包括文件不起作用？ [英] PHP Cron Job: Including file not working?

问题描述

我每天晚上都执行cron作业，但是由于某种原因，这就是说我尝试包含的文件不存在：

i run a cron job every night, but for some reason, it is saying that the file i try to include is inexistant:

Warning: require(../includes/common.php): failed to open stream: No such file or directory in /home/fini7463/public_html/cron/journeyNotifications.php on line 2
Fatal error: require(): Failed opening required '../includes/common.php' (include_path='.:/usr/lib/php:/usr/local/lib/php') in /home/fini7463/public_html/cron/journeyNotifications.php on line 2

代码如下：

set_include_path('/home/fini7463/public_html/includes/');
require 'common.php';

文件 common.php的位置如下

the file 'common.php' is located as follows

public_html => cron     => journeyNotifications.php
            => includes => common.php

我什至设置了include路径（如代码所示），但我仍然得到这个错误。

i even set the include path (as shown in the code), but i am still getting this error. what could the problem be?

谢谢！

推荐答案

请执行 require（'../ includes / common.php'），相对于当前工作目录遍历路径。

If you do require('../includes/common.php'), the path is traversed relative to the current working directory.

如果执行 require（'common.php'），则会在包含路径中搜索文件，并且

If you do require('common.php'), the file is searched in the include path, and in the directory of the script which calls the require().

要解决此问题，请首先在crontab中更改目录：

To solve this, first change directory in your crontab:

cd /home/fini7463/public_html; php -f cronjob.php

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