随机Cron工作 [英] random cron job

问题描述

我需要一个script1，它将每天随机执行一次script2。
我希望每天随机执行30次脚本2。
script1将在cron作业中设置。
有人可以帮忙实现它吗？
PS我不是程序员，所以需要准备一些东西，请

I need a script1 that will execute script2 at random times a day. I'm looking to execute the script2 around 30 times a day within random times. script1 will be set in the cron job. Could someone please help how to make it happen? PS I am not a programmer, so would need something ready to go, please

推荐答案

Seth的解决方案肯定有效，但是每天执行的次数会有所不同。如果您肯定要执行30次，而不是更多而不是更少，我建议使用cron条目，例如

Seth's solution certainly works, but the number of executions per day will differ. If you want definitely 30 executions, not more and not less, I propose using a cron entry like

0 0 * * * gen-executions.sh

和脚本 gen-executions.sh ：

#!/bin/bash
for number in $(seq 30)
do
    hour=$(( ${RANDOM}*24/32768 ))
    minute=$(( ${RANDOM}*60/32768 ))
    at -f /path/to/script.sh $(printf "%02d" ${hour}):$(printf "%02d" ${minute})
done

这会在一天中的随机时间使用at生成正好30次 /path/to/script.sh 的执行。

This generates exactly 30 executions of /path/to/script.sh at random times of the day using at.

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