使用Swift在iOS中创建安全随机数? [英] Create a Secure Random number in iOS using Swift?

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本文介绍了使用Swift在iOS中创建安全随机数?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

public func createSecureRandomKey(numberOfBits: Int) -> Any {
    let attributes: [String: Any] =
        [kSecAttrKeyType as String:CFString.self,
         kSecAttrKeySizeInBits as String:numberOfBits]

    var error: Unmanaged<CFError>?
    guard let privateKey = SecKeyCreateRandomKey(attributes as CFDictionary, &error) else {
        return ""
    }
    return privateKey
}

我正在尝试以上述方式创建安全随机数,但未返回任何内容,请问有人可以帮助我。谢谢。

I am trying to create Secure random number like above way, but returning nothing, Could any one please help me. Thanks.

推荐答案

您似乎在使用错误的函数。使用您的功能,您将生成一个新密钥。但是正如您的标题所述,您想生成安全的随机数。
为此,有一个函数叫做: SecRandomCopyBytes(:_:)

It looks like you are using the wrong function. With your function you are generating a new key. But as your title says you want to generate secure random numbers. For this there is a function called: SecRandomCopyBytes(::_:)

这里是摘自苹果官方文档的代码片段:

Here is a code snippet taken from the official apple documentation how to use it:

var bytes = [Int8](repeating: 0, count: 10)
let status = SecRandomCopyBytes(kSecRandomDefault, bytes.count, &bytes)

if status == errSecSuccess { // Always test the status.
    print(bytes)
    // Prints something different every time you run.
}

资料来源: Apple文档

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