在tcsh中生成序列号列表 [英] Generating sequential number lists in tcsh

问题描述

我一直在尝试找到一种解决方法，以便在tcsh中广泛定义连续编号列表，即而不是这样做：

I've been trying to find a workaround to defining lists of sequential numbers extensively in tcsh, ie. instead of doing:

i = ( 1 2 3 4 5 6 8 9 10 )

我想做这样的事情（知道它不起作用）

I would like to do something like this (knowing it doesn't work)

i = ( 1..10 )

这是在foreach循环中特别有用（我知道我可以用一段时间，只是想寻找一个替代方法。）。

This would be specially usefull in foreach loops (I know I can use while, just trying to look for an alternative).

环顾四周，我发现：

foreach $number (`seq 1 1 9`)
...
end

发现此处。他们说它将生成一个以1开头的数字列表，以1递增的数字以9结尾。

Found that here. They say it would generate a list of number starting with 1, with increments of 1 ending in 9.

我尝试过，但是没有用。显然seq不是命令。是否存在或这是完全错误的？

I tried it, but it didn't work. Apparently seq isn't a command. Does it exist or is this plain wrong?

还有其他想法吗？

推荐答案

seq 当然存在，但可能不在您的系统上，因为它不在POSIX标准中。我只是注意到您的命令中有两个错误。以下工作有效吗？

seq certainly exists, but perhaps not on your system since it is not in the POSIX standard. I just noticed you have two errosr in your command. Does the following work?

foreach number ( `seq 1 9` )
    echo $number
end

请注意，省略了美元符号和 seq 命令。

Notice the omission of the dollar sign and the extra backticks around the seq command.

如果仍然不起作用，您可以使用<$来模拟 seq c $ c> awk ：

If that still doesn't work you could emulate seq with awk:

foreach number ( `awk 'BEGIN { for (i=1; i<=9; i++) print i; exit }'` )

更新

另外两种选择：

Update

Two more alternatives:

1. 如果您的计算机没有 seq 它可能具有 jot （BSD / OSX）：

1. If your machine has no seq it might have jot (BSD/OSX):

foreach number ( `jot 9` )

我从未听说过 jot 之前，但在类固醇上看起来像 seq 。

I had never heard of jot before, but it looks like seq on steroids.

使用 bash 进行内置括号扩展：

Use bash with built-in brace expansion:

for number in {1..9}

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