重复printf参数 [英] Repeat printf arguments

问题描述

我找到了一些相关的帖子，但似乎没有任何作用。

I've found some related posts, but nothing seems to work.

我要为03-12实例重复相同的参数$ i。我确实在尝试使用某些nco运算符-但是printf语句使我很烦。

I want to repeat the same argument $i for the instances 03-12. I'm really trying to use some nco operators - but the printf statement is hanging me up.

#!/bin/csh
set i = 1
while ($i < 2)
    `printf O3_BDBP_1979ghg.cam.h0.00{03,04,05,06,07,08,09,10,11,12}-%02d.nc $i`
    @ i = $i + 1
end

输出为-因此它得到03的结果，但不是

The output is - so it gets it for 03 but not the rest.

printf: O3_BDBP_1979ghg.cam.h0.0004-%02d.nc: expected a numeric value

我也尝试过此语句（其他帖子）

I've also tried this statement (per other posts)

`printf O3_BDBP_1979ghg.cam.h0.00{03,04,05,06,07,08,09,10,11,12}-%1$02d.nc $i`

任何建议将不胜感激！

推荐答案

花括号为 printf 命令产生多个参数；仅第一个作为格式字符串，其余的作为第一个％1 的参数。换句话说，您正在获取

The braces produce multiple arguments for the printf command; only the first is treated as a format string, while the rest are treated as arguments for %1 in the first. In other words, you're getting

printf O3_BDBP_1979ghg.cam.h0.0003-%02d.nc O3_BDBP_1979ghg.cam.h0.0004-%02d.nc ... O3_BDBP_1979ghg.cam.h0.0012-%02d.nc $i

作为有效命令行。尝试嵌套循环：

as the effective command line. Try a nested loop instead:

#!/bin/csh
set i = 1
while ($i < 2)
    foreach j ( {03,04,05,06,07,08,09,10,11,12} )
        printf O3_BDBP_1979ghg.cam.h0.00%02-%02d.nc $j $i
    end
    @ i = $i + 1
end

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