Visual Studio代码：“程序定义了多个入口点” [英] Visual Studio Code: "Program has more than one entry point defined"

问题描述

我创建了一个 C＃项目， strong> Visual Studio代码 。该项目包含两个.cs文件，分别是 Addition.cs 和 Substraction.cs 。这两个文件都包含 main（）函数，并且两个文件都包含两个不同的程序。

I created a C# project using Visual Studio Code. This project contains two .cs files, Addition.cs and Substraction.cs. Both files contain a main() function and both files contain two different programs.

Addition.cs 文件中的代码：

using System;

namespace Example
{
    class Addition
    {
        static void Main(string[] args)
        {
            int sum = 3 + 2;
            Console.WriteLine(sum);
        }
    }
}

Substraction.cs中的代码文件

using System;

namespace Example
{
    class Substraction
    {
        static void Main(string[] args)
        {
            int sub = 3 - 2;
            Console.WriteLine(sub);
        }
    }
}

我要逐个测试这两个程序，但是当我这样做时

I want to test both the programs one by one, but when I do

dotnet run

"dotnet run"

上面的错误。

我知道由于同一项目中的两个main（）函数（入口点）会导致此错误，但是可以通过在Visual Studio中设置启动程序来解决此错误。项目。

I know because of two main() functions (entry points) in the same project is creating this error, but this can be overcome in Visual Studio by setting up a startup project.

我正在使用 Visual Studio代码，在这里我无法设置启动项目。

I am using Visual Studio Code, where I am unable to set up a startup project.

是是否可以在Visual Studio Code中为C＃项目设置入口点？

Is there a way to set up an entry point for a C# project in Visual Studio Code?

推荐答案

如果两个入口点都在同一项目，设置启动项目将无济于事。您需要设置启动 object 。

If both entry points are in the same project, setting the startup project wouldn't do anything anyway. You need to set the startup object.

这可以在完整版本的Visual Studio中的项目属性对话框中完成（查找或在.csproj文件中，通过设置 Project / PropertyGroup / StartupObject ：

This can be done in the project properties dialog in a full version of Visual Studio (look for "Startup object" under Application), or in the .csproj file by setting Project/PropertyGroup/StartupObject:

<StartupObject>Example.Addition</StartupObject>

或者考虑使用单个 Main（）命令行参数的入口点。

Alternatively consider using a single Main() entry point which takes a command-line argument.

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