Vanilla JS从“ active”类之外的所有其他元素中删除该类 [英] Vanilla JS remove class from all other elements besides 'active' class

问题描述

我正在尝试使用Vanilla JavaScript构建下拉菜单，但我想不出向单击的下拉菜单添加活动类别的最佳方法，然后同时从中删除所有其他活动类别兄弟元素。

I'm trying to build a dropdown menu with Vanilla JavaScript and I can't figure out the best way to add a class of active to the clicked dropdown menu, and then at the same time remove all other active classes from the sibling elements.

到目前为止，这是我所掌握的JS：

so far this is what I have as far as JS:

var _dropdowns = [].slice.call(document.getElementsByClassName('main-menu-li_dropdown'));

            _dropdowns.forEach(function(dropdowns) {
                dropdowns.addEventListener('click', function( event ){
                    event.preventDefault();
                    console.log(this !== event.target);
                    this.classList.toggle('active');
                });
            });

这是我的标记：

<nav id="main-nav">
    <ul>
        <li class="main-menu-li_dropdown">
            <a href="">link</a>
            <ul class="sub-nav">
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
            </ul>
        </li>
        <li class="main-menu-li_dropdown">
            <a href="">link</a>
            <ul class="sub-nav">
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
            </ul>
        </li>
        <li class="main-menu-li_dropdown">
            <a href="">link</a>
            <ul class="sub-nav">
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
            </ul>
        </li>
        <li class="main-menu-li_dropdown">
            <a href="">link</a>
            <ul class="sub-nav">
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
            </ul>
        </li>
        <li class="main-menu-li_dropdown">
            <a href="">link</a>
            <ul class="sub-nav">
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
                <li><a href="">link</a></li>
            </ul>
        </li>
    </ul>
</nav>

推荐答案

您可以遍历所有项目并删除类，然后将该类添加到单击的项目中。

You can loop through all of the items and remove the class, then add the class to the item that was clicked.

这里是一个示例：

http://jsbin.com/rivogelaqu/edit?html,js,output

let dropDowns = Array.from(document.querySelectorAll('.main-menu-li_dropdown'));

const handleClick = (e) => {
  e.preventDefault();
  dropDowns.forEach(node => {
    node.classList.remove('active');
  });
  e.currentTarget.classList.add('active');

}

dropDowns.forEach(node => {
  node.addEventListener('click', handleClick)
});

编辑：替代点击处理程序

这里是一个替代的单击处理程序，它避免了每次单击时的循环，而只是检查元素。

Here is an alternative click handler that avoids a loop on each click and just checks for the element. May be more performant.

const handleClick = (e) => {
  e.preventDefault();
  const active = document.querySelector('.active');
  if(active){
    active.classList.remove('active');
  }
  e.currentTarget.classList.add('active');
}

这篇关于Vanilla JS从“ active”类之外的所有其他元素中删除该类的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！