如何在盒子的左下角创建不对称三角形？ [英] How to create an asymmetric triangle at the bottom left corner of a box?

问题描述

我需要创建一个在左下角带有箭头的框。我的问题是得到不对称的三角形。

I need to create a box with an arrow at the left bottom corner. My problem is to get the asymmetric triangle.

在下面的示例中，框的底部边框的左下角有一个三角形：

Here an example for the bottom border of the box with an triangle at the left bottom corner:

这是我到目前为止的尝试：

This is my attempt so far:

.box {
  width: 150px;
  height: 75px;
  background-color: black;
  color: #fff;
  padding: 20px;
  position: relative;
  margin: 40px;
  float: left;
}

.box.arrow-bottom:after {
  content: " ";
  position: absolute;
  left: 0px;
  bottom: -15px;
  border-top: 15px solid black;
  border-right: 15px solid transparent;
  border-left: 15px solid transparent;
  border-bottom: none;
}

<div class="box arrow-bottom">
  This is a box with some content and an arrow at the bottom.
</div>

推荐答案

我稍微编辑了边框宽度，并添加了 transform：skewX（）。您可以使用正确的偏斜量。
另外，：after 更改为：before ，我和 left一起玩属性，并删除了权利。

希望对您有所帮助：

I edited the border width a bit, and added transform: skewX(). You may play with the right amount for the skew. In addition the :after changed to :before and I played with left property and removed the right.
hope it helps:

.box {
  width: 150px;
  height: 75px;
  background-color: black;
  color: #fff;
  padding: 20px;
  position: relative;
  margin: 40px;
  float: left;
}

.box.arrow-bottom:before {
  content: " ";
  position: absolute;
  left: 8px;
  bottom: -15px;
  border-top: 15px solid black;
  border-right: 0px solid transparent;
  border-left: 15px solid transparent;
  border-bottom: none;
  transform: skewX(20deg);
}

<div class="box arrow-bottom">
  This is a box with some content and an arrow at the bottom.
</div>

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