替换C字符串中的字符 [英] Replace characters in C string

问题描述

给出以下C字符串：

unsigned char *temp = (unsigned char *)[@"Hey, I am some usual CString" UTF8String]

如何用 other替换 usual以得到：嘿，我是其他CString。

How can I replace "usual" with "other" to get: "Hey, I am some other CString".

我不能使用 NSString 函数（ replaceCharactersInRange / replaceOccurencesOfString 等）。我必须将所有内容保持在较低的水平，因为我要处理的字符串恰好超过5MB，因此在iOS设备上替换（大约需要做很多替换）大约需要10分钟。

I cannot use NSString functions (replaceCharactersInRange/replaceOccurencesOfString, etc.) for performance reasons. I have to keep it all at low level, since the strings I'll be dealing with happen to exceed 5MB, and therefore the replacements (there will be a lot of replacements to do) take about 10 minutes on a iOS device.

推荐答案

Objective-C只是C上的一薄层。
如果您需要使用本机C字符串，则只需

Objective-C is a just thin layer over C. If you need to work with native C strings, just go ahead and do it.

此

替换C中的字符串的功能是什么？

似乎可以很好地解决您的问题。

seems to address your problem fairly well.

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