如何在不声明C类型的情况下将其转换为python整数？ -Python [英] How do I convert c types to python integers without having it declared? - Python

问题描述

呃，另一个编程问题的人，哈哈。

Ugh, another programming question guys, haha.

所以无论如何，我对使用python的ctype变得非常感兴趣。
ctypes基本上允许您在python中调用c变量（太棒了，我知道）
，所以这是您现在如何声明具有ctypes的变量：

So anyways, I became pretty interested in ctypes with python. ctypes basically allows you to call c variables within python (Awesome, I know) so here is how you declare variables with ctypes now:

import ctypes as c
class test(c.Structure):
   _fields_ = [
               ("example" , c.c_long),
               ...
              ]

不过，每当我使用字符串格式时，这就是问题：

Here's the thing though, whenever I use string formatting:

    print("test: %d" % (test.example)

它告诉我我需要它是一个Python整数，而不是C长。

it tells me that I needs it to be a Python Integer, not a C long.

在这里它变得复杂，因为没有真正声明example，所以我无法执行.value方法。它将返回语法错误。我无法将example声明为python整数，因为无法做到这一点。至少，据我所知）

Here's where it becomes complicated, because example isn't really declared, I can't do a .value method. It will return a syntax error. I can't declare example as a python integer because there is no way to do that. (at least, as far as I know)

任何帮助将不胜感激！

推荐答案

test 是一个类；创建的实例测试代替：

test is a class; create an instance of test instead:

import ctypes as c

class test(c.Structure):
   _fields_ = [("example" , c.c_long)]

t = test(5)
print(t.example) # -> 5
print("%d" % t.example) # -> 5

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