cURL到Invoke-Webrequest命令 [英] cURL to Invoke-Webrequest command

问题描述

谁能给我一个提示，如何将以下curl命令转换为PS Invoke-Webrequest？

Can anyone give me a hint, how to convert following curl command to PS Invoke-Webrequest ?

curl -d {\"password\":\"$password\"\} $vault/v1/auth/userpass/login/${login,,}

我对此有一些想法，但无法弄清楚如何完成此操作：

I have some thoughts on this, but cannot figure out, how to finish this:

$vault="3.3.3.3:8500"
$pair = (Get-Credential)
$params = ????
$login = $pair.getNetworkCredential().username
$pass = $pair.getNetworkCredential().password

Invoke-WebRequest $url -Method Post -Credential $pair -Body $params -UseBasicParsing

如何正确地传递$ params，例如curl请求？

How to correctly pass $params like in curl request?

推荐答案

参数应为哈希表 @ {} 。

$Params = @{
    Username="TestName";
    Password="TestPassword";
    Places = @("Here","There");
}

下面是使用名为jsonplaceholder的测试API的示例

Here is a example using a test API called jsonplaceholder

$url = 'https://jsonplaceholder.typicode.com/posts'

$params = @{
    title: 'foo'
    body: 'bar'
    userId:1
}

(Invoke-WebRequest $url -Method Post -Body $params -UseBasicParsing).content | ConvertFrom-JSON

响应

                                                     id
title: 'foo'                                       
body: 'bar'                                        
userId:1                                           

---------------------------------------------------  --
                                                    101

这篇关于cURL到Invoke-Webrequest命令的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！