如何打印JSON字符串的一部分并将其存储在变量中？ [英] How to print a part of a JSON string and store it in variable?
问题描述
我正在使用curl创建会话以登录到交换机。
我使用的脚本下面
I am using curl to create a session to log into the switch. Below the script that i use
curl --noproxy 10.23.193.1 -X POST http://10.23.193.1:80/rest/v3/login-sessions -d '{"userName":"admin", "password":"password"}'
执行此操作后，我得到以下输出
After this is executed I get the following output
{"uri":"/login-sessions","cookie":"sessionId=DfZNCFbfoc3LDuMgjLXRiS8ZmEo4MWENCOJM0Iu14R1uMT9kKqbe1Rx6AedmoeT"}
<首先只打印字符串的这一部分 sessionId = DfZNCFbfoc3LDuMgjLXRiS8ZmEo4MWENCOJM0Iu14R1uMT9kKqbe1Rx6AedmoeT
要第二次存储上面的字符串在变量中，以便我可以为后续操作调用相同的变量
Secondly I would want to know how to store the above string in a variable so that I could call the same variable for subsequent operations
我运行了以下命令，但没有任何输出。
I ran the following, but I am not getting any output.
curl --noproxy 10.23.193.1 -X POST http://10.23.193.1:80/rest/v3/login-sessions -d '{"userName":"admin", "password":"password"}' | grep -`E ""cookie":"
推荐答案
避免使用grep或sed这样的简单工具来解析JSON，因为它们无法正确处理引号或多行数据。最好使用支持JSON的程序，例如 jq 。
Avoid using simple tools like grep or sed to parse JSON as they won't handle things like quotes or multi-line data correctly. It's best to use a JSON-aware program such as jq.
使用jq既简单又强大：
With jq it's simple and robust:
curl ... | jq '.cookie'
要将Cookie存储在变量中，请使用- r 标志可让JQ打印出未加引号的原始字符串。
To store the cookie in a variable use the -r flag to have JQ print out the raw, unquoted string.
cookie=$(curl ... | jq -r '.cookie')
进一步阅读：
- jq Manual
- Parsing JSON with Unix tools
- How to parse JSON with shell scripting in Linux?
这篇关于如何打印JSON字符串的一部分并将其存储在变量中？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
