如何在Python 2.7中同时优化和找到两个方程的系数? [英] How do I optimize and find the coefficients for two equations simultaneously in Python 2.7?
问题描述
我有适合两个方程的数据集:
I have data sets that I would like to fit to two equations:
y1 = a1 + a2 * T / 2 + a3 * T ^ 2/3 + a4 * T ^ 3/4 + a5 * T ^ 4/5 + a6 / T
y2 = a1 * lnT + a2 * T + a3 * T ^ 2/2 + a4 * T ^ 3 / 3 + a5 * T ^ 4/4 + a7
y1 = a1 + a2 * T / 2 + a3 * T^2 / 3 + a4 * T^3 / 4 + a5 * T^4 / 5 + a6 / T
y2 = a1 * lnT + a2 * T + a3 * T^2 / 2 + a4 * T^3 / 3 + a5 * T^4 / 4 + a7
两个多项式共享一些参数(从a1到a5),所以我想同时拟合这两个方程。
The two polynomials share some parameters (a1 through a5) so I would like to fit these two equations simultaneously.
我尝试使用scipy.optimize.curve_fit:
I tried to do it with scipy.optimize.curve_fit:
import numpy as np
from scipy.optimize import curve_fit
def func(T, a1, a2, a3, a4, a5, a6, a7):
y1 = a1 + a2 * T / 2 + a3 * T**2 / 3 + a4 * T**3 / 4 + a5 * T**4/5 + a6/T
y2 = a1*np.log(T) + a2*T + a3 * T**2/2 + a4 * T**3/4 + a5 * T**4/4 + a7
return np.stack((y1, y2), axis = 1)
T = np.linspace(300, 1000, 20)
ydata_1 = np.array([
0.02139265, 0.40022353, 0.70653103, 0.95896469, 1.17025634,
1.34944655, 1.50316659, 1.63641239, 1.75303086, 1.85603601,
1.94782051, 2.03030092, 2.10501971, 2.17321829, 2.23589026,
2.29382086, 2.34761661, 2.39772787, 2.44446625, 2.48801814])
ydata_2 = np.array([
15.73868267, 16.14232408, 16.50633034, 16.83724622,
17.14016153, 17.41914701, 17.67752993, 17.91807535,
18.14310926, 18.35460465, 18.55424316, 18.74346017,
18.92347836, 19.09533317, 19.25989235, 19.41787118,
19.56984452, 19.71625632, 19.85742738, 19.99356154])
ydata = np.stack((ydata_1, ydata_2), axis = 1)
popt, pconv = curve_fit(f = func, xdata = T, ydata = ydata)
但是我得到了错误:
minpack.error: Result from function call is not a proper array of floats.
我什至不确定这是否是解决问题的正确方法。
I am not even sure if this is the right approach to solve the problem.
推荐答案
您可以尝试在二维空间中将y值的L_2范数最小化(即最小二乘拟合):
You can try minimising the L_2 norm (i.e. least squares fitting) in a 2 dimensional space for your y-values:
from scipy.optimize import minimize
def func(params):
a1, a2, a3, a4, a5, a6, a7 = params
y1 = a1 + a2 * T / 2 + a3 * T**2 / 3 + a4 * T**3 / 4 + a5 * T**4/5 + a6/T
y2 = a1*np.log(T) + a2*T + a3 * T**2/2 + a4 * T**3/4 + a5 * T**4/4 + a7
return np.sum((y1 - ydata_1) ** 2 + (y2 - ydata_2) ** 2)
T = np.linspace(300, 1000, 20)
ydata_1 = np.array([
0.02139265, 0.40022353, 0.70653103, 0.95896469, 1.17025634,
1.34944655, 1.50316659, 1.63641239, 1.75303086, 1.85603601,
1.94782051, 2.03030092, 2.10501971, 2.17321829, 2.23589026,
2.29382086, 2.34761661, 2.39772787, 2.44446625, 2.48801814])
ydata_2 = np.array([
15.73868267, 16.14232408, 16.50633034, 16.83724622,
17.14016153, 17.41914701, 17.67752993, 17.91807535,
18.14310926, 18.35460465, 18.55424316, 18.74346017,
18.92347836, 19.09533317, 19.25989235, 19.41787118,
19.56984452, 19.71625632, 19.85742738, 19.99356154])
# choose reasonable values for your 7 parameters here,
# i.e. close to the "right" answer, this may take a few tries
first_guess = [a1_0, a2_0, a3_0, a4_0, a5_0, a6_0, a7_0]
# here we run the minimisation
res = minimize(func, first_guess)
# this is an array of your best fit values for a1-a7
best_fit = res.x
但是,@ Stelios似乎是对的,因为您很难适应特定型号。
However, it seems that @Stelios is right in that you will have a hard time getting a good fit with your particular model.
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