如何使用cx_freeze在python中创建.EXE文件 [英] How to create .EXE file in python using cx_freeze

问题描述

我有一个使用python 3.2开发的应用程序，该应用程序具有内置模块（例如Tkinter，matplotlib，openpyxl），用户定义的模块&类（例如：draw_graph，generate_report），图标文件，日志文件，.csv，.docx等。我正在通过脚本（例如：testapplication.py）运行此应用程序

I have one application developed in python 3.2, which has inbuilt modules(ex: Tkinter, matplotlib, openpyxl), user defined modules & classes(ex: draw_graph, generate_report), icon files, log file, .csv, .docx etc. I am running this application from script(ex: testapplication.py)

我的安装文件为

import sys
from cx_Freeze import setup, Executable
exe = Executable(
    script=r"C:\Python32\testapplication.py",
    base="Win32GUI",
    )

setup(
    name = "TESTApp",
    version = "0.1",
    description = "An example",
    executables = [exe]
    )

现在，我想创建此应用程序的exe文件。有人可以建议我这样做吗？

Now I want to create a exe file of this application. can anyone please suggest me a way to do this?

推荐答案

这就是您需要做的。首先，将 script = r C：\Python32\testapplication.py 更改为 script = r testapplication.py

So this is what you need to do. For starters, change script=r"C:\Python32\testapplication.py" to script=r"testapplication.py"

然后，将需要转换的所有文件放入 C / python32 ，包括安装文件。然后，您需要执行的操作是打开命令行，然后键入以下命令：（假设您的cx_freeze文件名为setup.py）：

Then, put ALL the files to need to convert into C/python32 including the setup file. Then what you wan to do is get your command line up, and type the following commands: (assuming that you're cx_freeze file is named setup.py):

cd
cd python32
python setup.py build

然后在该目录中应该有一个包含exe文件的构建文件夹。

And then you should have a build folder in that directory containing the exe file.

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